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charle [14.2K]
3 years ago
7

Rewrite using standard notation: 354.2*10^-2

Mathematics
1 answer:
Murljashka [212]3 years ago
4 0

3.542 is the answer; you just need to move the decimal 2 places to the left.

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two verticies of paralellogram ABCD are A(-6,-1) and B(-5,3). The intersection of the diagonals, E, are (-2, 1/2). Determine the
masya89 [10]

Answer:

D(2,2)

Step-by-step explanation:

The diagonals of a parallelogram gram bisects each other.

Therefore E is the midpoint of AD.

Let the coordinates of D be (a,b).

By the midpoint rule:

( \frac{x_1+x_2}{2} ,\frac{y_1+y_2}{2}) = ( - 2, \frac{1}{2} )

This implies that:

( \frac{ - 6+a}{2} ,\frac{ - 1+b}{2}) = ( - 2, \frac{1}{2} )

This implies that:

( \frac{ - 6+a}{2} =  - 2 ,\frac{ - 1+b}{2} =  \frac{1}{2} )

( - 6+a =- 4 , - 1+b = 1 )  \\ ( a =- 4 + 6 , b = 1 + 1 )  \\ ( a =2 , b =2 )

7 0
3 years ago
Triangle ABC has coordinates A (0, 1) B (0, 2) and C (3,2). If Triangle ABC is equivalent to triangle EDF, what is the measure o
Elanso [62]

Answer:

  3

Step-by-step explanation:

Segment BC corresponds to segment DF. The length of BC is the distance between coordinates (0, 2) and (3, 2). These points are on the same horizontal line (y=2), so the distance between them is the difference of their x-coordinates: 3 - 0 = 3.

7 0
3 years ago
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Find the median<br> 23 ,15, 38 ,34 ,22, 2, 21 ,27 ,26 ,14, 32, 30, 19
xxTIMURxx [149]
First put them in ascending numerical order 
2, 14, 15, 19, 22, 21, 26, 27, 23, 30, 32, 34, 38
Then start to eliminate numbers by pair (the farthest number from each side) until you get to 1 or two numbers left (in the very middle)
in this case you will be left with 26, which means that the median is 26
3 0
3 years ago
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to tell whether the relationship is a proportional relationship if so than give the constant of proportionality
Katarina [22]
There is a relationship between if you notice all of the x values or numbers of minutes are being multiplied by 60 

So the constant would be 60
8 0
2 years ago
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There are bricks of silver and bricks of gold. When 5 silver bricks and 2 gold bricks are placed on a scale, the weight is 119 o
Illusion [34]

Answer:

The weight of one gold brick is 15 ounces and the weight of one silver brick is 22 ounces.

Step-by-step explanation:

Given,

Weight of 5 silver bricks and 2 gold bricks = 119 ounces.

And Weight of 4 silver bricks and 11 gold bricks = 302 ounces.

We have to find out weight of each type of brick.

Solution,

Let the weight of 1 silver brick be x.

And the weight of 1 gold brick be y.

Since the weight of 5 silver bricks and 2 gold bricks is 119 ounces.

So we can frame it in equation as;

5x+2y=119\ \ \ \ \ equation\ 1

Again,

The weight of 4 silver bricks and 11 gold bricks is 302 ounces.

So we can frame it in equation as;

4x+11y=302\ \ \ \ \ equation\ 2

Now, multiplying equation 1 by 4 and equation 2 by 5 we get;

4(5x+2y)=119\times4\\\\20x+8y=476\ \ \ \ \ equation\ 3

5(4x+11y)=302\times5\\\\20x+55y=1510\ \ \ equation\ 4

Now subtract equation 3 from equation 4, we get;

(20x+55y)-(20x+8y)=1510-476\\\\20x+55y-20x-8y=1034\\\\47y=1034\\\\y=\frac{1034}{47}\\\\y=22

On substituting yhe value of y in equation 1, we get;

5x+2y=119\\\\5x+2\times22=119\\\\5x+44=119\\\\5x=119-44=75\\\\x=\frac{75}{5}\\\\x=15

Thus the weight of one gold brick is 15 ounces and the weight of one silver brick is 22 ounces.

4 0
3 years ago
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