141,414 = 56% of P
Divide each side by 56% :
P = 141,414 / 0.56 = 252,525 performers.
Answer:
Probability that in a random sample of six cities, the sample mean would be more than 40 is 0.3372.
Step-by-step explanation:
We are given that the percent of births to mothers with less than a college education in all of the most populated cities in the U.S. has an average of 39.3 with a standard deviation of 4.1.
Assuming the data follows distribution. Also, a random sample of six cities is selected.
<em>Firstly, Let </em><em> = sample mean of six cities</em>
The z score probability distribution for sample mean is given by;
Z = ~ N(0,1)
where, = average percent of births = 39.3
= standard deviation = 4.1
n = sample of cities = 6
Probability that in a random sample of six cities, the sample mean would be more than 40 is given by = P( > 40)
P( > 40) = P( > ) = P(Z > 0.42) = 1 - P(Z 0.42)
= 1 - 0.66276 = 0.3372
Therefore, probability that the sample mean would be more than 40 is 0.3372.
Ok so first off you need to get rid of the clauses in the equation.
So 4.5 ( -4) becomes -18 and -2.5(3+28) becomes -77.5
-18 + 36 = 202 - 77.5
Now you are going to solve the equation.
18 = 122.5
Hope this helped ;),
Casey
That the answer for that question
Answer:
6
Step-by-step explanation:
In the y row, it decreases by 1 each time, so 1 decreased from 7 is 6. To plot this, we take the x and y values from each column and graph it. For example, the first row would be a point at (3, 8).