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Ksenya-84 [330]
3 years ago
15

HELP PLEASE QUICKLY!!!!!!!!!

Mathematics
1 answer:
Gennadij [26K]3 years ago
8 0
Side angle side or SAS
if you have any problems with my answer, write a comment and I will try to fix it.
Thanks!
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Ashley has 20 pieces of candy in a bag: 2 mint sticks, 4 jelly treats, and 14 fruit tart chews. If she eats one piece every 8 mi
AleksAgata [21]
The probability that her first treat is jelly is 4/20. Since she eats the candy and does not replace it, the probability the second treat is jelly would be 3/19 (1 less jelly and 1 less total candies). You would then multiply (4/20) by (3/19). That is your answer.
3 0
3 years ago
Write the function in standard form<br><br> f(x) = -4 (x - 6)^2 + 15
amid [387]

9514 1404 393

Answer:

  f(x) = -4x^2 +48x -129

Step-by-step explanation:

It usually works well to compute the square first. That is, simplify according to the order of operations.

  f(x) = -4(x^2 -12x +36) +15

  f(x) = -4x^2 +48x -144 +15

  f(x) = -4x^2 +48x -129

7 0
2 years ago
Read 2 more answers
What is the equation of a circle centered at the origin with radius 20?
Colt1911 [192]
We know that
the equation of a circle is
(x-h)²+(y-k)²=r²
where 
(h,k)-----> is the center
r--------> is the radius

is the center is the point (0,0) and radius  r=20
then
(h,k) is (0,0)

(x-0)²+(y-0)²=20²---------> (x)²+(y)²=400


the answer is
the option D.)  x2 + y2 = 400
3 0
3 years ago
Jack looks at a clock tower from a distance and determines that the angle of elevation of the top of the tower is 40°. John, who
zmey [24]

Answer:

18.7939 m

Step-by-step explanation:

-Let x be the distance between John and clock tower.

-Let y be the vertical distance from the eyes of the two men  standing to the top of the clock tower.

#Taking the right triangle ACD:

\Tan \ theta=\frac{Perpendicular \ Height}{Base}\\\\Tan \ 60\textdegree=\frac{y+1.5}{x}\\\\y=x \ Tan \ 60\textdegree -1.5

#Taking the right triangle ABD:

\Tan \ theta=\frac{Perpendicular \ Height}{Base}\\\\Tan \ 40\textdegree=\frac{y+1.5}{x+20}\\\\y=(x+20)\ Tan \ 40\textdegree -1.5

#We equate the two yo solve for x and y;

(x+20)\ Tan \ 40\textdegree -1.5=x\ Tan \ 60\textdegree -1.5\\\\(x+20)\ Tan \ 40\textdegree=x\ Tan \ 60\textdegree\\\\0.8391x+16.7820=1.7321x\\\\x=18.7939

Hence, John's distance from the tower's base is 18.7939 m

8 0
3 years ago
Help me with (d)(ii).<br><br> Thank you!
lord [1]
q=\frac{h^{2}-k^{2}}{3m}
Cross-multiplying and rearranging, we get:
k^{2}=h^{2}-3mq
or written without using latex:
k^2 = h^2 - 3mq
Can you finish now?
4 0
3 years ago
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