I THINK THE CORRECT ANSWER IS A!!!
If a2 -2ab + b2 = 9 and a![\begin{gathered} a^2-2ab+b^2=9 \\ aStep 1 factorize[tex]\begin{gathered} a^2-2ab+b^2=(a-b)^2 \\ \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20a%5E2-2ab%2Bb%5E2%3D9%20%5C%5C%20a%3C%2Fp%3E%3Cp%3E%EF%BB%BFStep%201%20%3C%2Fp%3E%3Cp%3Efactorize%3C%2Fp%3E%5Btex%5D%5Cbegin%7Bgathered%7D%20a%5E2-2ab%2Bb%5E2%3D%28a-b%29%5E2%20%5C%5C%20%20%5Cend%7Bgathered%7D)
then
[tex]\begin{gathered} (a-b)^2=9 \\ \sqrt{(a-b)^2}=\sqrt{9} \\ a-b=\pm3 \\ \\ aa-b=-3
It can, it just depends upon the slope
Do you know what the slope is?
Answer:
circumference is πd
d=112mm
22/7*112
=352mm
Step-by-step explanation:
Answer:
(a) rate of change = 8
(b) Function: y = 8x
(c) Domain: 0 ≤ x ≤ 2
Range: 0 ≤ y ≤ 16
Explanation:
Looks like a inverse variation sequence.
Inverse Variation formula: y = k(x)
Take two points: (1, 8), (2, 16)
Find the value of k which is constant also considered as <u>rate of change</u>.
<u>Insert values</u>:
===========
Equation: y = 8x
Domain lies in the x axis, Range lies in the y axis.
