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ZanzabumX [31]
3 years ago
8

In an ionic compound, the size of the ions affects the internuclear distance (the distance between the centers of adjacent ions)

, which affects lattice energy (a measure of the attractive force holding those ions together). Based on ion sizes, arrange these compounds by their expected lattice energy. Note that many sources define lattice energies as negative values. Please arrange by magnitude and ignore the sign.
Compunds: RbCl ,RbBr ,Rbl ,RbF
Chemistry
1 answer:
gregori [183]3 years ago
6 0

Answer:

The correct answer will be " RbF > RbCl > RbBr > Rbl".

Explanation:

The size of the given ions will be:

<u>RbCl:</u>

⇒  689kJ/mol

<u>RbBr:</u>

⇒  660kJ/mol

<u>Rbl:</u>

⇒  630kJ/mol

<u>RbF:</u>

⇒  785kJ/mol

Now according to the size, the arrangement will be:

⇒  (785kJ/mol) > (689kJ/mol) > (660kJ/mol) >(630kJ/mol)

⇒  RbF > RbCl > RbBr > Rbl

The bond among all opposite charging ions seems to be strongest whenever the ions were indeed small.

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8 0
3 years ago
What is the rate of the reaction when the initial concentration of no is 0.400 m and that of br2 is 0.245 m ?
Hoochie [10]
If the final concentration of NOBr = 0.250M
Change in concentration of NOBr = +0.250 M
Change in concentration of NO = -0.250 M
Change is concentration of Br2 = -0.125 M ( since number of moles of Br2 is 0.5 times the number of mole of NOBr)
Final concentration of NO = 0.400-0.250 = 0.150 M
Final concentration of Br2 = 0.245 - 0.125 M = 0.0120 M
Therefore;
Kc = conc (NOBr)^2/ ((conc NO)^2 ×(conc (Br2)
     = (0.250²)/(0.150²×0.120)
      = 23.148
      = 23.1 mol/dm³
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3 years ago
What is the mass of 40.34 x 10^23 H2 molecules at stp?
aev [14]
Every mol=6.22*10^23 <span>molecules and every mol of H2 Is 2 gram
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4 0
3 years ago
Read 2 more answers
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