Answer:
2C2H2 + 5O2 -----> 4CO2 + 2H2O
Explanation:
The question is incomplete, but i manage to find one question similar to this, and the remaining part is:
C2H2 + O2 -----> CO2 + H2O
To balance the equation, we need to use the priority order to balance, which is the following:
Metals > non metals > Oxygen > Hydrogen
According to this, we have non metals, oxygen and hydrogen in the above equation, let's balance first the carbon. We have 2 carbons in the products, and 1 in the products, then, we just put a 2 there:
C2H2 + O2 -----> 2CO2 + H2O
Now, the number of carbon is balanced, but the number of oxygen was altered, let's see how much do we need. We have 5 oxygens in the products, and 2 in the reactants, we can put a 2 next to the water, so the sum of the oxygens in the products will be 6, and then, a 3 in the reactants:
C2H2 + 3O2 -----> 2CO2 + 2H2O
Putting that, will alter the number of hydrogens, so we need to balance that putting a 2 in the reactants; however this will alter again the number of carbons, so we must change the number in the products for the carbon, changing the 2 by a 4:
2C2H2 + 3O2 -----> 4CO2 + 2H2O
Finally, we can change the number of oxygens in the reactants, from 3 to 5, to balance the equation:
2C2H2 + 5O2 -----> 4CO2 + 2H2O
And this is the final balanced equation
