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LenKa [72]
3 years ago
8

The number of molecules in 17.9 g of CO is

Chemistry
1 answer:
Gala2k [10]3 years ago
7 0

Answer:

3.85 × 10²³ molecules CO

General Formulas and Concepts:

<u>Atomic Structure</u>

  • Reading a Periodic Table
  • Compounds
  • Moles
  • Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

<u>Stoichiometry</u>

  • Using Dimensional Analysis

Explanation:

<u>Step 1: Define</u>

<em>Identify</em>

[Given] 17.9 g CO

[Solve] molecules CO

<u>Step 2: Identify Conversions</u>

Avogadro's Number

[PT] Molar Mass of C: 12.01 g/mol

[PT] Molar Mass of O: 16.00 g/mol

Molar Mass of CO: 12.01 + 16.00 = 28.01 g/mol

<u>Step 3: Convert</u>

  1. [DA] Set up:                                                                                                       \displaystyle 17.9 \ g \ CO(\frac{1 \ mol \ CO}{28.01 \ g \ CO})(\frac{6.022 \cdot 10^{23} \ molecules \ CO}{1 \ mol \ CO})
  2. [DA] Divide/Multiply [Cancel out units]:                                                           \displaystyle 3.8484 \cdot 10^{23} \ molecules \ CO

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

3.8484 × 10²³ molecules CO ≈ 3.85 × 10²³ molecules CO

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