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andreyandreev [35.5K]
3 years ago
10

The glow emitted by a substance exposed to external radiation is called

Chemistry
1 answer:
frosja888 [35]3 years ago
7 0
Fluorescence
when a substance absorbs external radiation in any form and gives of a glow or luminescence it is considered as Fluorescence. 
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How does density affect the layering of the Earth’s interior?
igor_vitrenko [27]

The density does not affect the earth's interior, the affection of pressure on the earths layers raises the temperature therefore making it have an effect on the layers.

5 0
3 years ago
Lime is added to a lake to neutralize the effects of acid rain. The pH value of the
OverLord2011 [107]

Answer:

The change in concentration of H+ ions is -9.99×10⁻⁵

Explanation:

When pH rises, we talk about neutralization and, there is a decline in proton's concentration.

pH lower than 7 is acid

pH higher than 7 is basic

Protons are neutralized by hydroxides to make water as this:

H₃O⁺   +  OH⁻  ⇄   H₂O

pH = - log [H₃O⁺]

[H₃O⁺] = 10^-pH

In conclussion: [H₃O⁺]₁ = 10⁻⁴ → 1×10⁻⁴

[H₃O⁺]₂ = 10⁻⁷ → 1×10⁻⁷

1×10⁻⁷- 1×10⁻⁴

The change in concentration of H+ ions is -9.99×10⁻⁵

4 0
3 years ago
What is an insulator
hammer [34]
A thing or substance used for a insulator, for example a substance that does not readily allow the passage of heat or sound
5 0
3 years ago
Read 2 more answers
A container with an initial volume of 1.0L is occupied by a gas at a pressure of 150kPa at 25'C. By changing the volume, the pre
Archy [21]

Answer:

Final Volume = 0.31L

Explanation:

Initial volume V1 = 1L

Initial pressure P1 = 150kPa

Initial temperature, T1 = 25'C + 273 = 298K

Final Pressure P2 = 600kPa

Final Temperature T2 = 100'C + 273 = 373K

Final Volume V2 = ?

The combined gas law is given as;

P1V1 / T1  = V2P2 / T2

150 * 1 / 298 = V2 * 600 / 373

V2 = 55950 / 178800 = 0.31L

4 0
3 years ago
According to the Gibbs free energy equation, G= H-T S, when could a high temperature make a reaction that was nonspontaneous at
Galina-37 [17]

Answer:

For the reaction to be spontaneous at high temperatures, ΔG < 0 and, ΔH > 0 and ΔS > 0.

Explanation:

According to the Gibbs free energy equation, for the reaction to be spontaneous at high temperatures when it was not spontaneous at low temperatures, the free energy change ΔG < 0.

Since ΔG = ΔH - TΔS where ΔH = enthalpy change and ΔS = entropy change,

For ΔG < 0 at high temperatures, ΔH > 0 and ΔS > 0. That is both ΔH and ΔS are positive at high temperatures.

<u>So, for the reaction to be spontaneous at high temperatures, ΔG < 0, and ΔH > 0 and ΔS > 0.</u>

7 0
3 years ago
Read 2 more answers
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