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Harlamova29_29 [7]
3 years ago
7

Most atoms follow the octet rule meaning they need ------ electrons to fill their valence shells. One important exception is H w

hich only needs ------------ electrons to fill its valence shell.
full they blank
Chemistry
2 answers:
Ilia_Sergeevich [38]3 years ago
6 0
1. 8 (oct means that eight, good way to remember this!)
2. hydrogen has ONE valence electron!

hope this helps :)
Serggg [28]3 years ago
5 0

Answer:

The octet rule means that atoms need a total of 8 valence electrons to fill their valence shell. Hydrogen only needs two to fill its valence shell.

Explanation:

All atoms except for hydrogen can hold a total of 8 valence electrons in their outer energy levels (2 in the s level, 6 in the p level). Hydrogen only has two electrons total, so it does not require more than the s level and two electrons to have a full valence.

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A metal X from two oxide A and B .3.oogm of A and B contain 0.72 and 1.16g of oxygen respectively.calculate the maases of metal
devlian [24]

Answer:

Explanation:

Firstly, we have to determine the mass of metal X. We can do that by interpreting the first and second statement mathematically.

Metal X can form 2 oxides (A and B).

A + B = 3g

The mass of oxygen in A is 0.72g and the mass of oxygen in B is 1.16g.

The mass of metal X in the two oxides will be the same because it's the same metal.

Thus, we represent the mass of the metal in the two oxides as 2X.

2X + 0.72 + 1.16 = 3

2X + 1.88 = 3

2X = 3 - 1.88

2X = 1.12

X = 0.56

<u>Thus, 0.56 g of the metal combines with 0.72g of oxygen in A and 1.16 g of oxygen in B.</u>

Thus, mass of metal (X) in 1g of oxygen in A is

0.56g ⇒ 0.72g

X ⇒ 1

X = 1 × 0.56/0.72

X = 0.78 g

Hence, 0.78g of the metal will combine with 1g of oxygen for A

Also, mass of metal (X) in 1g of oxygen in B is

0.56g ⇒ 1.16g

X ⇒ 1g

X = 1×0.56/1.16

X = 0.48 g

Thus, 0.48g of the metal will combine with 1g of oxygen for B

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Answer:

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7 0
3 years ago
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Assuming it behaves as an ideal gas, calculate the density of sulfur dioxide, so2, at stp.
Arisa [49]
Hello!

At Standard Pressure and Temperature, an ideal gas has a molar density of  0,04464 mol/L.

So, we need to apply a simple conversion factor to calculate the density of Sulfur Dioxide using the molar mass of Sulfur Dioxide.

\frac{0,04464 mol SO_2}{1 L SO_2}* \frac{64,066 g SO_2}{1 mol SO_2}=2,8599 g/L

So, the Density of Sulfur Dioxide (SO₂) at STP is 2,8599 g/L

Have a nice day!


6 0
3 years ago
Read 2 more answers
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