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galina1969 [7]
3 years ago
7

Consider a 1.6 × 10-3 M solution of HNO3. Which of the following statements is NOT true? Consider a 1.6 × 10-3 M solution of HNO

3. Which of the following statements is NOT true? This solution could dissolve metal. This solution could neutralize a base. This solution would turn litmus to red. This solution has a pH of 11.20. none of the above
Chemistry
1 answer:
Serjik [45]3 years ago
3 0

Answer:

This solution has a pH of 11.20

Explanation:

HNO3 is a strong acid known to ionize completely in solution. Being a strong acid, a low pH value is expected. As expected, an acid will display the following properties:

This solution could dissolve metal.

This solution could neutralize a base.

This solution would turn litmus to red.

The pH of this solution is obtained from -log[H+]

pH = -log(1.6 × 10-3)= 2.796

Hence the statement; This solution has a pH of 11.20 is not correct.

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Answer:

Correc option: Br^- \, , Kr

Explanation:

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Determine the standard enthalpy of formation in kJ/mol for NO given the following information about the formation of NO2 under s
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Answer:

90.3 kJ/mol

Explanation:

Let's consider the following thermochemical equation.

2 NO(g) + O₂(g) → 2 NO₂(g)  ∆H°rxn = –114.2 kJ

We can find the standard enthalpy of formation for NO using the following expression.

∆H°rxn = 2 mol × ΔH°f(NO₂(g)) - 2 mol × ΔH°f(NO(g)) - 1 mol × ΔH°f(O₂(g))

∆H°rxn = 2 mol × ΔH°f(NO₂(g)) - 2 mol × ΔH°f(NO(g)) - 1 mol × 0 kJ/mol

∆H°rxn = 2 mol × ΔH°f(NO₂(g)) - 2 mol × ΔH°f(NO(g))

ΔH°f(NO(g)) = (2 mol × ΔH°f(NO₂(g)) - ∆H°rxn) / 2 mol

ΔH°f(NO(g)) = (2 mol × 33.2 kJ/mol + 114.2 kJ) / 2 mol

ΔH°f(NO(g)) = 90.3 kJ/mol

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Mass plus atomic and number

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