103^2-102^2
The property that applies here is a^2-b^2 = (a+b)(a-b)
so the answer is 103^2-102^2=(102+103)*(103-102)= numerically it is 205( as 103+102 = 205 and 103-102 = 1.....so 205*1 = 205)
The thing is that usually the factorization ends at (102+103)(102-103) ......
Answer: 4 is 3 5 is 8 6 is 15 and 7 is 24
Step-by-step explanation: i am not sure if this is math but yeah just do 20% of each number
Answer:
Step-by-step explanation:
X = y + 13 where x and y are Juanita and her cousin's age.
x + y >= 103
substituting for x:-
y + 13 + y >=103
2y >= 90
y >= 45
Answer is 45.
