Answer:
The expected total amount of time the operator will spend on the calls each day is of 210 minutes.
Step-by-step explanation:
Normal Probability Distribution:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean
and standard deviation
, the z-score of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
n-values of normal variable:
Suppose we have n values from a normally distributed variable. The mean of the sum of all the instances is
and the standard deviation is 
Calls to a customer service center last on average 2.8 minutes.
This means that 
75 calls each day.
This means that 
What is the expected total amount of time in minutes the operator will spend on the calls each day
This is M, so:

The expected total amount of time the operator will spend on the calls each day is of 210 minutes.
If you add the 3/4s with the 2 1/4 hour breaks it would be 1 hour and 1 fourth.
Then you take 10-1/2 hours and subtract it by 1 hour and 1 fourth.
So you would get 9-1/4 hours
Answer:
7x - 3
Step-by-step explanation:
3x+(4x-3)
Remove parenthesis
3x + 4x - 3
Combine like terms
3x + 4x = 7x
7x - 3
The vertical stretch of f(x) to g(x) is a factor of 5
<h3>How to determine the dilation?</h3>
The functions are given as:
f(x) = x
g(x) = 5x
Substitute f(x) = x in g(x) = 5x
g(x) = 5f(x)
In th above equation, the factor is 5.
5 is greater than 1 (this means vertical stretch)
Hence, the vertical stretch of f(x) to g(x) is a factor of 5
Read more about dilation at:
brainly.com/question/3457976
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Answer:

Step-by-step explanation:
