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vaieri [72.5K]
2 years ago
8

PLEASE HELP ASAP I NEED IT QUICK

Mathematics
1 answer:
marishachu [46]2 years ago
4 0

Answer:

C would be the answer!

Step-by-step explanation:

The line goes down so its a negative and if you count the dots it is -3/5 which double is - 6/10:)

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12 fluid ounces of sweat an hour 
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2. Find the value of x in the triangle. Round your answer to the nearest tenth of a degree. Show your work.
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Sophia downloaded 600 vacation pictures. Of the pictures, 63% show the beach. About how many pictures show the beach?
Mashcka [7]

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378 pictures

Step-by-step explanation:

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2 years ago
A vertical cylinder is leaking water at a rate of 4m3/sec. If the cylinder has a height of 10m and a radius of 2m, at what rate
Lyrx [107]

Answer:

Therefore the rate change of height is  \frac{1}{\pi} m/s.

Step-by-step explanation:

Given that a vertical cylinder is leaking water at rate of 4 m³/s.

It means the rate change of volume is 4 m³/s.

\frac{dV}{dt}=4 \ m^3/s

The radius of the cylinder remains constant with respect to time, but the height of the water label changes with respect to time.

The height of the cylinder be h(say).

The volume of a cylinder is V=\pi r^2 h

                                                 =( \pi \times 2^2\times h)\ m^3

\therefore V= 4\pi h

Differentiating with respect to t.

\frac{dV}{dt}=4\pi \frac{dh}{dt}

Putting the value \frac{dV}{dt}

\Rightarrow 4\pi \frac{dh}{dt}=4

\Rightarrow \frac{dh}{dt}=\frac{4}{4\pi}

\Rightarrow \frac{dh}{dt}=\frac{1}{\pi}

The rate change of height does not depend on the height.

Therefore the rate change of height is  \frac{1}{\pi} m/s.

3 0
2 years ago
Suppose ten students in a class are to be grouped into teams. (a) If each team has two students, how many ways are there to form
ValentinkaMS [17]

Answer:

(a) There are 113,400 ways

(b) There are 138,600 ways

Step-by-step explanation:

The number of ways to from k groups of n1, n2, ... and nk elements from a group of n elements is calculated using the following equation:

\frac{n!}{n1!*n2!*...*nk!}

Where n is equal to:

n=n1+n2+...+nk

If each team has two students, we can form 5 groups with 2 students each one. Then, k is equal to 5, n is equal to 10 and n1, n2, n3, n4 and n5 are equal to 2. So the number of ways to form teams are:

\frac{10!}{2!*2!*2!*2!*2!}=113,400

For part b, we can form 5 groups with 2 students or 2 groups with 2 students and 2 groups with 3 students. We already know that for the first case there are 113,400 ways to form group, so we need to calculate the number of ways for the second case as:

Replacing k by 4, n by 10, n1 and n2 by 2 and n3 and n4 by 3, we get:

\frac{10!}{2!*2!*3!*3!}=25,200

So, If each team has either two or three students, The number of ways  form teams are:

113,400 + 25,200 = 138,600

6 0
3 years ago
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