An ordered pair which makes both inequalities true is (-1, -3).
<h3>What is an ordered pair?</h3>
An ordered pair is a pair of two points that are commonly written in a fixed order within parentheses as (x, y), which represents the x-coordinate or x-axis (abscissa) and the y-coordinate or y-axis (ordinate) on the coordinate plane of any graph.
Next, we would test the ordered pair with the given system of inequalities in order to determine which is true.
For ordered pair (-3, 5), we have:
y < –x + 1
5 < -(-3) + 1
5 < 3 + 1
5 < 4 (False).
For ordered pair (-2, 2), we have:
y < –x + 1
2 < -(-2) + 1
2 < 2 + 1
2 < 3 (True).
y > x
2 > -2 (True)
For ordered pair (-1, -3), we have:
y < –x + 1
-3 < -(-1) + 1
-3 < 1 + 1
-3 < 2 (True).
y > x
-3 > -1 (False)
For ordered pair (0, -1), we have:
y < –x + 1
-(-1) < -(0) + 1
1 < 1
1 < 1 (False).
y > x
-1 > 0 (False)
Read more on inequality here: brainly.com/question/27166555
#SPJ1
Answer:
£103.70
Step-by-step explanation:
Payment per hour = £8.50
Overtime payment = 1.4 × 8.50
= £11.90
Ben worked for 11 hours.
Normal time = 8 hours
Overtime = 3 hours
Total earnings = (8 hours × 8.50) + (3 hours × 11.90)
= £68 + £35.7
= £103.70
Ben earned £103.70 for working for 11 hours
The generic equation of a third degree polynomial is given by:
y = ax ^ 3 + bx ^ 2 + cx + d
We must make a system of equations to find the values of a, b, c, d.
We have then:
For (1, 3):
3 = a (1) ^ 3 + b (1) ^ 2 + c (1) + d
3 = a + b + c + d
For (2, -2):
-2 = a (2) ^ 3 + b (2) ^ 2 + c (2) + d
-2 = 8a + 4b + 2c + d
For (3, -5):
-5 = a (3) ^ 3 + b (3) ^ 2 + c (3) + d
-5 = 27a + 9b + 3c + d
For (4.0):
0 = a (4) ^ 3 + b (4) ^ 2 + c (4) + d
0 = 64a + 16b + 4c + d
We obtain the following system of equations:
3 = a + b + c + d
-2 = 8a + 4b + 2c + d
-5 = 27a + 9b + 3c + d
0 = 64a + 16b + 4c + d
Whose solution is:
a = 1
b = -5
c = 3
d = 4
The polynomial will then be:
y = x ^ 3 - 5x ^ 2 + 3x + 4
Answer:
y = x ^ 3 - 5x ^ 2 + 3x + 4
Answer:
There is evidence to claim that the proportion of drug and alcohol use is higher locally than nationally.
Step-by-step explanation:
Given that a recent drug survey showed an increase in the use of drugs and alcohol among local high school seniors as compared to the national percent.
Let p1 be the proportion of local seniors and p2 national seniors.
(right tailed test at 5% significance level)
Group I II
Success 69 60 129
Total 100 100 200
p 0.69 0.6 0.645
q 0.31 0.4 0.355
se 0.046249324 0.048989795 0.033836002
p diff 0.09
Std error 0.03384
Z 2.659574468 0
p 0.00391
we find that p value is 0.00391 <0.05
Hence we reject null hypothesis
There is evidence to claim that the proportion of drug and alcohol use is higher locally than nationally.
