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2 years ago

What is the area of the triangle ?

Mathematics

1 answer:

bezimeni [28]2 years ago

8 0

from the question, (-2,2) and (1,2) have the same y value so you can use that as your base and easily find the perpendicular height using the y axis since it's parallel to the x axis.

the third point, (0,-6), to the base is your height

use the sum of the positive of the y values to find your height (because height can't be negative): 6+2 = 8

area of a triangle = 1/2 bh = 1/2 x 3 x 8 = 12

Note: 1/2 bh only works because (-2,2) and (1,2) form a line parallel to the x axis

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Answer:

The required equation is: $\mathbf{f(x)=\frac{3}{4}x-\frac{29}{4}}$

Step-by-step explanation:

We need to find equation from the table given

x f(x)

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We can write equation in the form of $y=mx+b$

where m is slope and b is y-intercept.

Finding Slope

We can used the slope formula to find slope: $Slope=\frac{y_2-y_1}{x_2-x_1}$

From the table we have: $x_1=3, y_1=-5, x_2=7, y_2=-2$

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$Slope=\frac{y_2-y_1}{x_2-x_1}\\Slope=\frac{-2-(-5)}{7-3} \\Slope=\frac{-2+5}{7-3}\\Slope=\frac{3}{4}$

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Now, finding y-intercept

Using the slope $m=\frac{3}{4}$ and point (3,-5) we can find y-intercept

$y=mx+b\\-5=\frac{3}{4}(3)+b\\-5=\frac{9}{4}+b\\b=-5-\frac{9}{4}\\b=\frac{-5*4-9}{4}\\b=\frac{-20-9}{4}\\b=\frac{-29}{4}$

The y-intercept is $b=\frac{-29}{4}$

So, the equation having slope $m=\frac{3}{4}$ and y-intercept $b=\frac{-29}{4}$ will be:

$y=mx+b\\y=\frac{3}{4}x-\frac{29}{4}$

The required equation is: $\mathbf{f(x)=\frac{3}{4}x-\frac{29}{4}}$

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