Ask question

Ask question

All categories

3 years ago

7

The Stock Market Alexander is a stockbroker. He earns 14% commission each week. Last week, he sold $7,200 worth of stocks. How m

uch did he make last week in commission? If he averages that same amount each week, how much did he make in commission in 2011? mmiccion

1 answer:

Mrrafil [7]3 years ago

6 0

Answer:

44304

Step-by-step explanation:

You might be interested in

When a number x is multiplied by 4 the result is 2/5 what is the vaule of x

topjm [15]

2/5 as a decimal is 0.4
4*0.1=0.4
meaning x is 0.1

7 0

4 years ago

Read 2 more answers

Find the derivative

zalisa [80]

First use the chain rule; take $y=\dfrac{x+5}{x^2+3}$ . Then

$\dfrac{\mathrm df}{\mathrm dx}=\dfrac{\mathrm df}{\mathrm dy}\cdot\dfrac{\mathrm dy}{\mathrm dx}$

By the power rule,

$f(x)=y^2\implies\dfrac{\mathrm df}{\mathrm dy}=2y=\dfrac{2(x+5)}{x^2+3}$

By the quotient rule,

$y=\dfrac{x+5}{x^2+3}\implies\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{(x^2+3)\frac{\mathrm d(x+5)}{\mathrm dx}-(x+5)\frac{\mathrm d(x^2+3)}{\mathrm dx}}{(x^2+3)^2}$

$\implies\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{(x^2+3)-(x+5)(2x)}{(x^2+3)^2}$

$\implies\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{3-10x-x^2}{(x^2+3)^2}$

So

$\dfrac{\mathrm df}{\mathrm dx}=\dfrac{2(x+5)}{x^2+3}\cdot\dfrac{3-10x-x^2}{(x^2+3)^2}$

$\implies\dfrac{\mathrm df}{\mathrm dx}=\dfrac{2(x+5)(3-10x-x^2)}{(x^2+3)^3}$

6 0

3 years ago

Put 0.6 as a percent

Tanya [424]

Answer:

6%

Step-by-step explanation:

8 0

3 years ago

(#4) which IS NOT a linear equation?

kifflom [539]

The correct is g for your question

8 0

3 years ago

Find the equation of a line that contains the points (−3,−1) and (−4,−7). Write the equation in slope-intercept form

ikadub [295]

Answer:

y = -8x -25

Step-by-step explanation:

The 2-point form of the equation of a line is useful when you are given 2 points.

y = (y2 -y1)/(x2 -x1)(x -x1) +y1

y = (7 -(-1))/(-4 -(-3))(x -(-3)) +(-1)

y = 8/-1(x +3) -1

y = -8x -25

7 0

3 years ago