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4 years ago

AC = 64, AB = 7x + 8, and BC = 3x + 6, Find BC.

Mathematics

1 answer:

iVinArrow [24]4 years ago

6 0

Answer:

Step-by-step explanation:

AC = 64
AB = 7x + 8
BC = 3x + 6

<u>Since AC = AB + BC</u>

7x + 8 + 3x + 6 = 64
10x + 14 = 64
10x = 50
x = 50/10
x = 5

------------------

BC = 3x + 6 = 3*5 + 6 = 21

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3 years ago

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joja [24]

Answer:

Step-by-step explanation:

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3 years ago

What is the answer to this question?

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3 years ago

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3 years ago

What is 5 pi over 3 radians in degrees? <br><br> 60° <br><br> 120° <br><br> 210° <br><br> 300°

Wittaler [7]

<h3>( 5π/3 ) radians = 300°</h3>

<h3>Further explanation</h3>

Firstly , let us learn about trigonometry in mathematics.

Suppose the ΔABC is a right triangle and ∠A is 90°.

<h3>sin ∠A = opposite / hypotenuse</h3><h3>cos ∠A = adjacent / hypotenuse</h3><h3>tan ∠A = opposite / adjacent </h3>

There are several trigonometric identities that need to be recalled, i.e.

$cosec ~ A = \frac{1}{sin ~ A}$

$sec ~ A = \frac{1}{cos ~ A}$

$cot ~ A = \frac{1}{tan ~ A}$

$tan ~ A = \frac{sin ~ A}{cos ~ A}$

Let us now tackle the problem!

There are several units for angles for example :

<em>1 revolution = 360°</em>

<em>2π radian = 360°</em>

<em>1 radian = (180/π)°</em>

If we would like to convert (5π/3) radians into degrees , then :

$1 ~ rad = ( \frac{180}{\pi} )^o$

$\frac{5 \pi}{3} ~ rad = ( \frac{5 \pi}{3} \times \frac{180}{\pi} )^o$

$\frac{5 \pi}{3} ~ rad = ( \frac{900 {\pi}}{3 \pi} )^o$

$\large {\boxed {\frac{5 \pi}{3} ~ rad = 300^o} }$

<h3>Learn more</h3>

Calculate Angle in Triangle : brainly.com/question/12438587
Periodic Functions and Trigonometry : brainly.com/question/9718382
Trigonometry Formula : brainly.com/question/12668178

<h3>Answer details</h3>

Grade: College

Subject: Mathematics

Chapter: Trigonometry

Keywords: Sine , Cosine , Tangent , Opposite , Adjacent , Hypotenuse

4 0

3 years ago

Read 2 more answers