The quadratic equation is given by:
y = 3x² + 10x - 8
The standard equation of a parabola is given by:
y = ax² + bx + c
Where a, b, c are constants
At point (4, 80):
80 = a(4)² + b(4) + c
16a + 4b + c = 80 (1)
At point (-3, -11):
-11 = a(-3)² + b(-3) + c
9a - 3b + c = -11 (2)
At point (-1, -15):
-15 = a(-1)² + b(-1) + c
a - b + c = -15 (3)
Solving equations 1, 2 and 3 simultaneously gives:
a = 3, b = 10, c = -8
Therefore the quadratic equation becomes:
y = 3x² + 10x - 8
Find out more on quadratic equation at: brainly.com/question/1214333
<u><em>28.1 feet</em></u>
<u><em></em></u>
<em><u>explaination</u></em>
<u><em>\cos U = \frac{\text{adjacent}}{\text{hypotenuse}}=\frac{9.6}{x}</em></u>
<u><em>cosU= </em></u>
<u><em>hypotenuse</em></u>
<u><em>adjacent</em></u>
<u><em> </em></u>
<u><em> = </em></u>
<u><em>x</em></u>
<u><em>9.6</em></u>
<u><em> </em></u>
<u><em> </em></u>
<u><em>\cos 70=\frac{9.6}{x}</em></u>
<u><em>cos70= </em></u>
<u><em>x</em></u>
<u><em>9.6</em></u>
<u><em> </em></u>
<u><em> </em></u>
<u><em>x\cos 70=9.6</em></u>
<u><em>xcos70=9.6</em></u>
<u><em>Cross multiply.</em></u>
<u><em>\frac{x\cos 70}{\cos 70}=\frac{9.6}{\cos 70}</em></u>
<u><em>cos70</em></u>
<u><em>xcos70</em></u>
<u><em> </em></u>
<u><em> = </em></u>
<u><em>cos70</em></u>
<u><em>9.6</em></u>
<u><em> </em></u>
<u><em> </em></u>
<u><em>Divide each side by cos 70.</em></u>
<u><em>x=\frac{9.6}{\cos 70}=28.0685\approx 28.1\text{ feet}</em></u>
<u><em>x= </em></u>
<u><em>cos70</em></u>
<u><em>9.6</em></u>
<u><em> </em></u>
<u><em> =28.0685≈28.1 feet</em></u>
<u><em>Type into calculator and roundto the nearest tenth of a foot.</em></u>
Answer:
-6
Step-by-step explanation:
h(x) = -3x – 12 becomes h(-2) = -3(-2) – 12 = -6
Answer:
800
Step-by-step explanation:
In order to form triangle PQT and quadrilateral TQRS, point T must lie on line PS which is 16 cm. long.
If the ratio of PT to TS is 5:3 and the total length of PS is 16, then PT must be 10 and TS must be 6 (10 + 6 =16) and 10:6 is the same ratio as 5:3. Another way to think about it is 5/3 = 10/6.
Now you have all the lengths that you need to find the areas of the quadrilateral and the triangle.
Make sure you draw a diagram of it!!
