- <em><u>C</u></em>
- <em><u>B</u></em>
- <em><u>C</u></em>
<em><u>hope </u></em><em><u>it</u></em><em><u> helps</u></em>
<em><u>#</u></em><em><u>c</u></em><em><u>a</u></em><em><u>r</u></em><em><u>r</u></em><em><u>y</u></em><em><u> </u></em><em><u>on</u></em><em><u> learning</u></em>
The temperature outside a plane flying at an altitude of 5 kilometers is -17°C.
Given that,
- The ground temperature at the airport is 10 °C.
- The decrease in temperature is 5.4°C for each & every rise in 1 kilometer.
Based on the above information, the temperature outside should be
The decrease in the temperature should be
= 5.4×5
= 27°C
Now the final temperature is
= 10 - 27
= -17°C
Therefore we can conclude that the temperature outside a plane flying at an altitude of 5 kilometers is -17°C.
Learn more: brainly.com/question/20459283
Answer:
my appleas arw yellow
Step-by-step explanation:
Answer:
70 apples
Step-by-step explanation:
We can use a ratio to solve
7 apples x apples
-------------- = -------------
50 name 500 names
Using cross products
7 * 500 = 50x
Divide by 50
7 * 500/50 = 50x/50
70 =x
6 + 12 = 18
18/9 = 2
The answer is 2
Hope this helps