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Scrat [10]
3 years ago
9

1 Kepler's third law relates the period of a ciosed orbit to its

Biology
2 answers:
Diano4ka-milaya [45]3 years ago
7 0

Answer:

major axis

gravity

hyperbolic

Pluto

Newton’s

Aristotle developed the geocentric model that states the sun, moon, and stars seem to revolve around the Earth. Copernicus developed the heliocentric model that states the sun is at the center and other celestial bodies of the solar system orbit around it. The Sun-Earth-Moon System is based on the heliocentric model

Explanation:

valkas [14]3 years ago
7 0

Answer:

1. Kepler's third law relates the period of a ciosed orbit to its <u>major axis</u>.

2 The sun's <u>gravity</u> keeps planets in our solar system in orbit around the sun.

3. Comets are examples of bodies that complete parabolic or <u>hyperbolic</u> orbits.

4. The orbits of all the planets in the solar system are slightly elliptical with the exception of <u>pluto</u>.

5. Kepler's laws describe how objects move through space; <u>Newton's</u> laws describe why objects move in this way.

6. The geocentric and heliocentric models are models describing the universe. 'Geo' means earth, while 'helio' means sun.

The main difference between the two models is that the geocentric model describes earth as the centre of the universe; while the heliocentric model describes the sun as being the centre of the universe.

Explanation:

  • The geocentric model was proposed by a Greek philosopher called Aristotle who believed that the universe was perfect and finite. He stated that the sun, moon, the planets and stars all revolve around the earth.
  • The heliocentric model was developed by a Polish astronomer called Copernicus who argued that the sun, rather than the earth, was the centre of the universe, and all planets revolve around it.
  • Contradictory evidence in the motions of the planetary bodies led to the rejection of the geocentric model by another Greek called Galileo, who went on to support the heliocentric theory.
  • His view was highly controversial at the time, but it prevailed, and today we know the system as the Solar system.
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Given data:

● Angular velocity of the turntable ω = 33 rev/min

Therefore,

ω = 33 rev/min

ω = 33rev/min × 2π rad/rev × 1 min/60 sec = 3.45 rad/s

● The distance of the watermelon seed from the axis of rotation r = 7.8 cm = 0.078 m

● μs = the coefficient of static friction

Section a:

The seed is undergoes circular motion and it is been effected by centripetal acceleration.

ac = rω^2

ac = 0.078 × 3.45^2

ac = 0.9284 m/s^2

Therefore,

the centripetal acceleration of the seed is 9.274 m/s^2

Section b:

If the seed is observed not to slip at the course of the circular motion, then the supplied frictional force given by the seed and surface of turntable would at least be equivalent to the centripetal force working on the seed.

Centripetal Force = Frictional Force

mrω^2 = μsmg

μs = rω^2 /g

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------------

9.81

μs = 0.09464

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