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Scilla [17]
3 years ago
9

The owner of a gift shop keeps holiday decorations in a rectangular box that has a a volume of 30 cubic feet. The length of the

box is 4 feet and the hight of the box is 2.5 feet. What is the width of the box?
Mathematics
1 answer:
Aliun [14]3 years ago
6 0

Answer:

Width of box is 3 feet

Step-by-step explanation:

Given,

Volume of a box = 30 cubic feet

Length of box= 4 feet

Height of box = 2.5 feet

We need to find width of box.

Since, Volume of box = Length * Height * width

  Now plug values for volume, length and height in the above formula and find width.

So,

  30  = 4 * 2.5 * Width

30 = 10 * width

Width = 30 /10 = 3 feet

Hence width of box is 3 feet.

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mezya [45]

Answer:

784000

Step-by-step explanation:

Given data

Profit =  700000

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=12/100* 700000

=0.12* 700000

=84000

Hence the profit made last years was

=84000+700000

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5 0
2 years ago
The map of a mall is overlaid with a numeric
Veseljchak [2.6K]

Answer:

\sqrt{118}<em> or 10.8627805 </em>

Step-by-step explanation:

Start by taking the difference of each value of both points

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<u>Take the square root of this value </u>

<u />\sqrt{118}<u />

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3 years ago
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vesna_86 [32]
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7 0
4 years ago
(-8+1.5)x4/5 <br><br> Help please
fenix001 [56]

Answer:

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Step-by-step explanation:

-8+1.5 = -6.5

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7 0
2 years ago
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Evaluate the following equation: integral from 3 to infinity: 1/(x-2)^(3/2) dx
Bond [772]

The formula in solving the integral of the infinity of 3 is  ∫3<span>∞?</span>(1<span>)÷((</span>x−2<span><span>)<span><span>(3/</span><span>2)</span></span></span>)</span><span>dx</span>

Substitute the numbers given then solve

limn→inf∫3n(1/((n−2)(3/2))dn

limn→inf[−2/(n−2−−−−−√)−(−2/3−2−−−−√)

=0+2=2

 

Solve for the integral of 2 when 2 is approximate to 0. Transpose 2 from the other side to make it -2

∫∞3(x−2)−3/2dx=(x−2)−1/2−1/2+C

(x−2)−1/2=1x−2−−−−√

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<span> </span>

8 0
4 years ago
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