<span>Step 1:
</span>
<span> (((22•5x2) + 25x) - 12x) - 15)))
</span>
<span>The first term is, <span> <span>20x2</span> </span> its coefficient is <span> 20 </span>.
The middle term is, <span> +13x </span> its coefficient is <span> 13 </span>.
The last term, "the constant", is <span> -15
</span></span>
<span>step 2 above, -12 and 25
<span>20x2 - 12x</span> + 25x - 15
Step-4 : Add up the first 2 terms, pulling out like factors :
4x • (5x-3)
Add up the last 2 terms, pulling out common factors :
5 • (5x-3)
Step-5 : Add up the four terms of step 4 :
(4x+5) • (5x-3)
Which is the desired factorization</span>Final result :<span> (5x - 3) • (4x + 5)
</span>
To check if a piecewise defined function is continuous, you need to check how the pieces "glue" together when you step from one domain to the other.
So, the question is: what happens at x=3? If you reach x=3 from values slightly smaller than 3, you obey the rule f(x)=log(3x). So, as you approach 3, you get values closer and closer to
Similarly, if you reach x=3 from values slightly greater than 3, you obey the rule f(x)=(4-x)log(9). So, as you approach 3, you get values closer and closer to
So, the function is continuous at x=3, because both pieces approach log(9) as x approaches 3.
Answer:
1.x=15
2.<A=29
Step-by-step explanation:
(2x-1)+(3x+9)+(6x+7)=180
2x-1+3x+9+6x+7=180
11x+15=180
11x=180-15
11x=165
x=165/11
x=15
2.<A=2x-1
<A=2*15-1
<A=30-1
<A=29
Lower case numbers for points
