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Citrus2011 [14]

3 years ago

12

A table top is in the shape of a trapezoid. The lengths of the trapezoid's parallel sides are 48 in. and 40 in. The height of th

e trapezoid is 24 in. What is the area of the tabletop?

2 answers:

lakkis [162]3 years ago

7 0

A=a+b2h=48+402·24=1056

shepuryov [24]3 years ago

7 0

The answer is 1056in. The perimeter is 136in, now all you need is the formula.

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3 out of 20 boxes are damaged what percent is damaged?

Goshia [24]

The answer is 15%.
Just divide 3 and 20.

7 0

3 years ago

Read 2 more answers

The base of a triangular prism is an isosceles right triangle with a hypotenuse of 72−−√ centimeters. The height of the prism is

Amiraneli [1.4K]

Answer:

Step-by-step explanation:

Surface area = lateral area + 2(area of base)

Lateral area = perimeter of base * height.

Because it is a isosceles right triangle, both sides are equal.

$x^{2} +x^{2}$ = 72

2 $x^{2}$ = 72. Divide both sides by 2

$x^{2}$ = 36. Square both sides.

x = 6.

So the perimeter of the base = 6 + 6 + $\sqrt{72}$ = 20.485281374239

Lateral area = 20.485281374239 * 7 = 143.397 $cm^{2}$

Area of base is (1/2)base * height.

(1/2)(6)(6) = 18

Using the surface area formula

surface area = 143.397 + 2(18) = 179.4 $cm^{3}$

4 0

3 years ago

What is the value of x

Andru [333]

The answer to your question is 54 because you have to bring over 2 to 3 and it would be 1x then bring over 52 and add it to 2 = 54

8 0

3 years ago

Three Texas drovers met on a highway and began to dicker as follows:

Alik [6]

Answer:

Jim's: 7
Duke's: 21
Hank's: 11

Step-by-step explanation:

Let J, D, and H represent the drove sizes of Jim, Duke, and Hank.

2(H -6 + 1) = (J +6 -1) . . . . . Hank's offer

3(D -14 +1) = (H +14 -1) . . . . Duke's offer

6(J -4 +1) = (D +4 -1) . . . . . . Jim's offer

These equations can be simplified to ...

2H - J = 15

3D - H = 52

6J - D = 21

__

<u>Solution</u>

Adding twice the second equation to the first gives ...

2(3D -H) +(2H -J) = 2(52) +(15)

6D -J = 119

Adding 6 times the third equation to this one gives ...

6(6J -D) +(6D -J) = 6(21) +(119)

35J = 245

J = 7

Using this value in the third equation gives ...

6(7) -D = 21

42 -21 = D = 21

Using the value of J in the first equation gives ...

2H -7 = 15

H = (15 +7)/2 = 11

Then the solution is (J, D, H) = (7, 21, 11).

Jim's drove had 7 animals; Duke's drove had 21 animals; Hank's drove had 11 animals.

5 0

3 years ago

Solve the proportion. When necessary, round to the nearest tenth? 36/j = 7/20

erastovalidia [21]

Work is provided in the image attached.

3 0

3 years ago