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Citrus2011 [14]
3 years ago
12

A table top is in the shape of a trapezoid. The lengths of the trapezoid's parallel sides are 48 in. and 40 in. The height of th

e trapezoid is 24 in. What is the area of the tabletop?
Mathematics
2 answers:
lakkis [162]3 years ago
7 0
A=a+b2h=48+402·24=1056
shepuryov [24]3 years ago
7 0
The answer is 1056in. The perimeter is 136in, now all you need is the formula.  
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Given side lengths of 40 cm, 70 cm, and 80 cm, how many triangles can be constructed?
Salsk061 [2.6K]
One with 40cm being the side, 70 diagonal and 80 as the base so it is a right angle triangle
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When rounding to the nearest hundred i become 500 what numbers could i be
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Any number above 450 
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A common inhabitant of human intestines is the bacterium Escherichia coli. A cell of this bacterium in a nutrient-broth medium d
nikitadnepr [17]

Answer:

a) k=2.08 1/hour

b) The exponential growth model can be written as:

P(t)=Ce^{kt}

c) 977,435,644 cells

d) 2.033 billions cells per hour.

e) 2.81 hours.

Step-by-step explanation:

We have a model of exponential growth.

We know that the population duplicates every 20 minutes (t=0.33).

The initial population is P(t=0)=58.

The exponential growth model can be written as:

P(t)=Ce^{kt}

For t=0, we have:

P(0)=Ce^0=C=58

If we use the duplication time, we have:

P(t+0.33)=2P(t)\\\\58e^{k(t+0.33)}=2\cdot58e^{kt}\\\\e^{0.33k}=2\\\\0.33k=ln(2)\\\\k=ln(2)/0.33=2.08

Then, we have the model as:

P(t)=58e^{2.08t}

The relative growth rate (RGR) is defined, if P is the population and t the time, as:

RGR=\dfrac{1}{P}\dfrac{dP}{dt}=k

In this case, the RGR is k=2.08 1/h.

After 8 hours, we will have:

P(8)=58e^{2.08\cdot8}=58e^{16.64}=58\cdot 16,852,338= 977,435,644

The rate of growth can be calculated as dP/dt and is:

dP/dt=58[2.08\cdot e^{2.08t}]=120.64e^2.08t=2.08P(t)

For t=8, the rate of growth is:

dP/dt(8)=2.08P(8)=2.08\cdot 977,435,644 = 2,033,066,140

(2.033 billions cells per hour).

We can calculate when the population will reach 20,000 cells as:

P(t)=20,000\\\\58e^{2.08t}=20,000\\\\e^{2.08t}=20,000/58\approx344.827\\\\2.08t=ln(344.827)\approx5.843\\\\t=5.843/2.08\approx2.81

3 0
3 years ago
A factory robot recently examined some bulbs, of which 4 were flawed and 26 were not. Considering this data, how many flawed bul
ASHA 777 [7]

Answer:

2

Step-by-step explanation:

Given that:

Flawed bulbs = 4

Not flawed = 26

Total examined = (flawed + not flawed)

Total examined = (4 + 26) = 30

P(flawed) = flawed / total

P(flawed) = 4 / 30 = 0.1333333

If 15 is examined :

Expected number of flawed bulbs :

(4/30) * 15 = 2

4 0
3 years ago
How do you do these questions ? i need help:(
IrinaVladis [17]

Answer:

(x,y) all you have to do is fill in the x and y and find the equation it matches to

Step-by-step explanation:

hope this helps plz give brainliest

8 0
3 years ago
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