All categories

3 years ago

A ball has a diameter of 7 inches. What is the volume

Mathematics

2 answers:

matrenka [14]3 years ago

8 0

179.5 inches to the power of 3 that’s the answer

Veseljchak [2.6K]3 years ago

3 0

Answer:

179,5 inches³

Step-by-step explanation:

Hello !

d = 2r => r = d/2 = 7in/2 = 3.5 inches

V = 4π·r³/3

= 4·3.14·(3.5in)³/3

= 538.51in³/3

≈ 179,5 inches³

You might be interested in

Parents of students at a middle school

Contact [7]

Answer:

(B). 319

Step-by-step explanation:

$\frac{42}{60}$ = $\frac{x}{456}$

$\frac{7}{10}$ = $\frac{x}{456}$

x = $\frac{7*456}{10}$ ≈ 319

6 0

2 years ago

Read 2 more answers

3. Determine the lateral and total surface area of the pyramid.

tatuchka [14]

I think it’s is 12865

7 0

2 years ago

Evaluate cosA/2 given cosA=-1/3 and tanA >0

mote1985 [20]

Answer:

$\bold{cos\dfrac{A}{2} = -\dfrac{1}{\sqrt3}}$

Step-by-step explanation:

Given that:

$cosA=-\dfrac{1}3$

and

$tanA > 0$

To find:

$cos\dfrac{A}{2} = ?$

Solution:

First of all,we have cos value as negative and tan value as positive.

It is possible in the 3rd quadrant only.

$\dfrac{A}{2}$ will lie in the 2nd quadrant so $cos\dfrac{A}{2}$ will be negative again.

Because Cosine is positive in 1st and 4th quadrant.

Formula:

$cos2\theta =2cos^2(\theta) - 1$

Here $\theta = \frac{A}{2}$

$cosA =2cos^2(\dfrac{A}{2}) - 1\\\Rightarrow 2cos^2(\dfrac{A}{2}) =cosA+1\\\Rightarrow 2cos^2(\dfrac{A}{2}) =-\dfrac{1}3+1\\\Rightarrow 2cos^2(\dfrac{A}{2}) =\dfrac{2}3\\\Rightarrow cos(\dfrac{A}{2}) = \pm \dfrac{1}{\sqrt3}$

But as we have discussed, $cos\dfrac{A}{2}$ will be negative.

So, answer is:

$\bold{cos\dfrac{A}{2} = -\dfrac{1}{\sqrt3}}$

7 0

2 years ago

Need help please!!!!!!

Neporo4naja [7]

Answer:

x = 13.75

Step-by-step explanation:

(4x + 5) - 10 = 50

4x + 5 - 10 = 50

4x - 5 = 50

4x = 50 + 5

4x = 55

x = 55/4

x = 13.75

8 0

2 years ago

The point (3, -4) is on the terminal side of an angle 0 . What is cos 0 ?

RSB [31]

Draw it
cos=oposite side/hypothuse

oposite side=y=-4
hypotonuse=distance from (0,0) to (3,-4)
which is $D=\sqrt{3^2+(-4)^2}=\sqrt{9+16}=\sqrt{25}=5$

so it would be -4/5

5 0

3 years ago