Please help me find h(6)

Solve using the quadratic formula: (Standard form 1st!) 2x^2-2x=24

Flura [38]

Answer:

4, -3

Step-by-step explanation:

The quadratic formula is $\frac{-b+-\sqrt{b^2-4ac} }{2a}$ .

When using the formula for both the negative and positive value of the sqrt, you will get:

x = 4, -3

5 0

3 years ago

7) In the barn there are 17 animals. Some are cows and some are ducks. There are 54 legs in all. Which system of equations below

nata0808 [166]

Answer: Either A or B

Step-by-step explanation:

Both A and B are the same answers, but the main answer should be

c+d=17, 4c+2d =54

C represents the number of cows and D represents the number ducks. The two and fours in front of the variables represents the number of legs the repesctive animal has.

c+d would mean how many animals are in the barn. Feel free to clarify the two same answers

4 0

3 years ago

• The manager of a bookstore uses the equation 8 = p - 3.5 to find the price a student pays for a book.

Ivahew [28]

Answer:

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Two large and 1 small pumps can fill a swimming pool in 4 hours. One large and 3 small pumps can also fill the same swimming poo

kolezko [41]

Let x and y be the unit rates at which one large pump and one small pump works, respectively.

Two large/one small operate at a unit rate of

(1 pool)/(4 hours) = 0.25 pool/hour

so that

2x + y = 0.25

One large/three small operate at the same rate,

(1 pool)/(4 hours) = 0.25 pool/hour

x + 3y = 0.25

Solve for x and y. We have

y = 0.25 - 2x ==> x + 3 (0.25 - 2x) = 0.25

==> x + 0.75 - 6x = 0.25

==> 5x = 0.5

==> x = 0.1

==> y = 0.25 - 2 (0.1) = 0.25 - 0.2 = 0.05

In other words, one large pump alone can fill a 1/10 of a pool in one hour, while one small pump alone can fill 1/20 of a pool in one hour.

Now, if you have four each of the large and small pumps, they will work at a rate of

4x + 4y = 4 (0.1) + 4 (0.05) = 0.6

meaning they can fill 3/5 of a pool in one hour. If it takes time t to fill one pool, we have

(3/5 pool/hour) (t hours) = 1 pool

==> t = (1 pool) / (3/5 pool/hour) = 5/3 hours

So it would take 5/3 hours, or 100 minutes, for this arrangement of pumps to fill one pool.

6 0

3 years ago

The most common form of color blindness is an inability to distinguish red from green. However, this particular form of color bl

Alecsey [184]

Answer:

(a) The correct answer is P (CBM) = 0.79.

(b) The probability of selecting an American female who is not red-green color-blind is 0.996.

(c) The probability that neither are red-green color-blind is 0.9263.

(d) The probability that at least one of them is red-green color-blind is 0.0737.

Step-by-step explanation:

The variables CBM and CBW are denoted as the events that an American man or an American woman is colorblind, respectively.

It is provided that 79% of men and 0.4% of women are colorblind, i.e.

P (CBM) = 0.79

P (CBW) = 0.004

(a)

The probability of selecting an American male who is red-green color-blind is, 0.79.

Thus, the correct answer is P (CBM) = 0.79.

(b)

The probability of the complement of an event is the probability of that event not happening.

Then,

P(not CBW) = 1 - P(CBW)

= 1 - 0.004

= 0.996.

Thus, the probability of selecting an American female who is not red-green color-blind is 0.996.

(c)

The probability the woman is not colorblind is 0.996.

The probability that the man is not color- blind is,

P(not CBM) = 1 - P(CBM)

= 1 - 0.004

= 0.93.

The man and woman are selected independently.

Compute the probability that neither are red-green color-blind as follows:

$P(\text{Neither is Colorblind}) = P(\text{not CBM}) \times P(\text{not CBW})\\ = 0.93 \times 0.996 \\= 0.92628\\\approx 0.9263$

Thus, the probability that neither are red-green color-blind is 0.9263.

(d)

It is provided that a one man and one woman are selected at random.

The event that “At least one is colorblind” is the complement of part (d) that “Neither is Colorblind.”

Compute the probability that at least one of them is red-green color-blind as follows:

$P (\text{At least one is Colorblind}) = 1 - P (\text{Neither is Colorblind})\\ = 1 - 0.9263 \\= 0.0737$

Thus, the probability that at least one of them is red-green color-blind is 0.0737.

6 0

3 years ago