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3 years ago

Which statement is an example of the Identity Property of Multiplication?

1 answer:

7 0

The Identity Property of Multiplication states that any number multiplied by 1 does not change. Therefore the correct answer would be: 8 • 1 = 8.

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Luke’s basketball team went to an amusement park at the end of the season. The cost of the admission for 5 coaches and 12 player

Finger [1]

Answer:

The admission cost for each player was 22.50.

Step-by-step explanation:

Given:

Luke’s basketball team went to an amusement park at the end of the season.

The cost of the admission for 5 coaches and 12 players was 407.50.

The admission cost for each coach was 27.50.

Now, to find the admission cost for each player.

Total admission cost = 407.50.

Number of coaches = 5.

Admission cost for each = 27.50.

So, the cost of admission of all coaches:

$27.50\times 5$

$=137.50.$

Then, we deduct the cost of admission of all coaches from the total admission cost:

$407.50-137.50$

$=270.$

Remaining cost = 270.

Number of player = 12.

Now, to get the admission cost for each player we divide the remaining cost by number of players:

$270\div 12$

$=22.50.$

Therefore, the admission cost for each player was 22.50.

7 0

3 years ago

A diamond today cost ten dollars more than twice what it cost last year.The sum of the cost (last year and this year) is $2500.

nadya68 [22]

Answer:

The cost of the diamond last year is x = $ 830

Step-by-step explanation:

Let the cost of diamond last year = x

the cost of diamond present year = y

Given that diamond today cost ten dollars more than twice what it cost last year.

⇒ y = 2 x + 10 ------ (1)

The sum of the cost (last year and this year) is = $ 2500

⇒ x + y = $ 2500 -------- (2)

Put the value of y in equation (2) from equation (1), we get

⇒ 2 x + 10 + x = $ 2500

⇒ 3 x = 2490

⇒ x = $ 830

& y = 2500 - 830

⇒ y = $ 1670

Therefore the cost of the diamond last year is x = $ 830

6 0

3 years ago

1. Eating together, Gertrude and Heathcliff spend 40 minutes each day at a local sunflower bird feeder. In preparation for their

vagabundo [1.1K]

40min*1.05=42min they spent 42 min together

ps: check the multiplication it's 01:30 and I did that in head

8 0

3 years ago

The graph h = −16t^2 + 25t + 5 models the height and time of a ball that was thrown off of a building where h is the height in f

Thepotemich [5.8K]

Answer:

part 1) 0.78 seconds

part 2) 1.74 seconds

Step-by-step explanation:

step 1

At about what time did the ball reach the maximum?

Let

h ----> the height of a ball in feet

t ---> the time in seconds

we have

$h(t)=-16t^{2}+25t+5$

This is a vertical parabola open downward (the leading coefficient is negative)

The vertex represent a maximum

The x-coordinate of the vertex represent the time when the ball reach the maximum

Find the vertex

Convert the equation in vertex form

Factor -16

$h(t)=-16(t^{2}-\frac{25}{16}t)+5$

Complete the square

$h(t)=-16(t^{2}-\frac{25}{16}t+\frac{625}{1,024})+5+\frac{625}{64}$

$h(t)=-16(t^{2}-\frac{25}{16}t+\frac{625}{1,024})+\frac{945}{64}\\h(t)=-16(t^{2}-\frac{25}{16}t+\frac{625}{1,024})+\frac{945}{64}$

Rewrite as perfect squares

$h(t)=-16(t-\frac{25}{32})^{2}+\frac{945}{64}$

The vertex is the point $(\frac{25}{32},\frac{945}{64})$

therefore

The time when the ball reach the maximum is 25/32 sec or 0.78 sec

step 2

At about what time did the ball reach the minimum?

we know that

The ball reach the minimum when the the ball reach the ground (h=0)

For h=0

$0=-16(t-\frac{25}{32})^{2}+\frac{945}{64}$

$16(t-\frac{25}{32})^{2}=\frac{945}{64}$

$(t-\frac{25}{32})^{2}=\frac{945}{1,024}$

square root both sides

$(t-\frac{25}{32})=\pm\frac{\sqrt{945}}{32}$

$t=\pm\frac{\sqrt{945}}{32}+\frac{25}{32}$

the positive value is

$t=\frac{\sqrt{945}}{32}+\frac{25}{32}=1.74\ sec$

8 0

3 years ago

What is the ratio for sine

Sphinxa [80]

Answer:

Blank 1: opposite

Blank 2: adjacent

Blank 3: opposite

Blank 4: adjacent

Step-by-step explanation:

There is a trigonometric acronym for this which is:

Soh Cah Toa

Soh means that sine is opposite over hypotenuse.

Cah means that cosine is adjacent over hypotenuse.

Toa means that tangent is opposite over adjacent.

Let me actually write these out as fractions:

sine is $\frac{\text{opposite}}{\text{hypotenuse}}$

cosine is $\frac{\text{adjacent}}{\text{hypotenuse}}$

tangent is $\frac{\text{opposite}}{\text{adjacent}}$

Blank 1: opposite

Blank 2: adjacent

Blank 3: opposite

Blank 4: adjacent

4 0

3 years ago