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3 years ago

What is the reciprocal of 3 and 3/7

Mathematics

2 answers:

Vikentia [17]3 years ago

8 0

Answer:

1/3 and 7/3

Step-by-step explanation:

Reciprocal of 3: 1/3

Reciprocal of 7/3: 3/7

velikii [3]3 years ago

4 0

Answer:

7/3 and 1/3

Step-by-step explanation:

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Mr. Lincoln buys juice and water for the school picnic. A pack of 8 juice boxes ca

alexgriva [62]

Answer:

5x + 3y = 95

8x + 6y = 170

x = 10 ; y = 15

Step-by-step explanation:

Let :

x = pack of juice boxes

y = pack of water bottles

Pack of juice box = $5

Pack of water bottles = $3

Amount of money spent :

5x + 3y = $95

Number of drinks purchased :

8x + 6y = 170

Using both equations ;

5x + 3y = 95 - - - (1)

8x + 6y = 170 - - - (2)

Multiply (1) by 6 and (2) by 3

30x + 18y = 570

24x + 18y = 510

Subtract :

6x = 60

x = 60 / 6

x = 10

Put x = 10 in (1)

5(10) + 3y = 95

50 + 3y = 95

3y = 95 - 50

3y = 45

y = 45 / 3

y = 15

x = 10 ; y = 15

4 0

3 years ago

Write an inequality involving the variable x that describes the set of numbers graphed.

Anna [14]

Since it does not include 0 in the inequality, nor does it include any numbers below 0, it must be $\boxed{x\ \textgreater \ 0}$ .

3 0

3 years ago

Someone tell me if I’m right

otez555 [7]

Answer:

Yes you are correct

Step-by-step explanation:

3 0

2 years ago

A hoop, a uniform solid cylinder, a spherical shell, and a uniform solid sphere are released from rest at the top of an incline.

Serjik [45]

Answer:

Step-by-step explanation:

Given

Hoop, Uniform Solid Cylinder, Spherical shell and a uniform Solid sphere released from Rest from same height

Suppose they have same mass and radius

time Period is given by

$t=\sqrt{\frac{2h}{a}}$ ,where h=height of release

a=acceleration

$a=\frac{g\sin \theta }{1+\frac{I}{mr^2}}$

Where I=moment of inertia

a for hoop

$a=\frac{g\sin \theta }{1+\frac{mr^2}{mr^2}}$

$a=\frac{g\sin \theta }{2}$

a for Uniform solid cylinder

$a=\frac{g\sin \theta }{1+\frac{mr^2}{2mr^2}}$

$a=\frac{2g\sin \theta }{3}$

a for spherical shell

$a=\frac{g\sin \theta }{1+\frac{2mr^2}{3mr^2}}$

$a=\frac{3g\sin \theta }{5}$

a for Uniform Solid

$a=\frac{g\sin \theta }{1+\frac{2mr^2}{5mr^2}}$

$a=\frac{5g\sin \theta }{7}$

time taken will be inversely proportional to the square root of acceleration

$t_1=k\sqrt{2}=1.414k$

$t_2=k\sqrt{\frac{3}{2}}=1.224k$

$t_3=k\sqrt{\frac{5}{3}}=1.2909k$

$t_4=k\sqrt{\frac{7}{5}}=1.183k$

thus first one to reach is Solid Sphere

second is Uniform solid cylinder

third is Spherical Shell

Fourth is hoop

3 0

3 years ago

Un grupo de 4 amigos va al cine y las entradas les han costado 24$.¿cuanto pagaria en total un grupo de 7 amigos por sus entrada

vodka [1.7K]

4 entries are 24 so one entry is 24/4 = 6

so 7 friends pay 6*7 = 42

5 0

3 years ago