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3 years ago

What is the length of the hypotenuse of the right triangle shown?

Mathematics

1 answer:

chubhunter [2.5K]3 years ago

3 0

Answer:

Step-by-step explanation:

Use the Pyhagorean theorem:

$leg^2+leg^2=hypotenuse^2$

We have the lengths of legs 12 and 16. Substitute:

$c^2=12^2+16^2\\\\c^2=144+256\\\\c^2=400\to c=\sqrt{400}\\\\c=20$

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If tan 0=3/4 find csc0

jasenka [17]

Answer:

tanθ = 3/4 p/b

using Pythagoras theorem

H² = P² + b²

H² = 3²+ 4²

H² = 25

H = 5

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3 years ago

G Calculations Lesson 1

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Step-by-step explanation:

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2 years ago

Read 2 more answers

Multiplying decimals and Dividing (all)

Triss [41]

Step-by-step explanation:

step 1. (-0.4)(0.16) = -0.064

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3 years ago

Please help?!

Anton [14]

Answer:

Δ PQT ~ Δ QRS .....{S-S-S test for similarity}...Proof is below.

Step-by-step explanation:

Given:

In Δ PQT

PQ = 30 ft

QT = 28 ft

TP = 20 ft

In Δ QRS

QR = 15 ft

RS = 14 ft

SQ = 10 ft

To Prove:

Δ PQT ~ Δ QRS

Proof:

First we consider the ratio of the sides

$\frac{PQ}{QR}=\frac{30}{15} = \frac{2}{1}$ ..............( 1 )

$\frac{QT}{RS}=\frac{28}{14} = \frac{2}{1}$ ..............( 2 )

$\frac{TP}{SQ}=\frac{20}{10} = \frac{2}{1}$ ..............( 3 )

So By equation ( 1 ), ( 2 ) and ( 3 ) we get

$\frac{PQ}{QR}=\frac{QT}{RS} = \frac{TP}{SQ}$

Now in Δ PQT and Δ QRS we have

$\frac{PQ}{QR}=\frac{QT}{RS} = \frac{TP}{SQ}$

Which are corresponding sides of a similar triangle in proportion.

∴ Δ PQT ~ Δ QRS .....{S-S-S test for similarity}...Proved

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3 years ago

I need help plz help

barxatty [35]

I think the answer is c

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3 years ago