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ehidna [41]
3 years ago
13

Select linear or nonlinear

Mathematics
2 answers:
Nesterboy [21]3 years ago
6 0
First and last are linear
seraphim [82]3 years ago
5 0
Linear because i said so
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Roots of x^2+8x+9 by finding in quadratic formula
gladu [14]
The quadratic formula is -b + or - the square root of b squared - 4 times the a value and c value over 2a. So the roots would be -1.354249 and -6.645751. I believe these are the roots. 
4 0
3 years ago
What is 7 2/6 plus 8 5/6
yulyashka [42]
7  2/6 + 8  5/6
= (7 x 6 + 2)/6 + (8 x 6 + 5)/6
= (42 + 2)/6 + (48 + 5)/6
= 44/6 + 53/6
= (44 + 53)/6
= 97/6
= 16  1/6
3 0
3 years ago
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Please help!! I don't get this.
Lynna [10]
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3 0
3 years ago
Use the remainder theorem to find the remainder of 2x^4 + x^2 - 10x -1 divided by x +2.
Svetllana [295]

Remainder Theorem says that if there is any Polynomial equation P(x), which is to be divided by (x - a) then remainder can be calculated by substituting value of a in equation P(x).  

2x^{4} +x^{2}-10x-1 = P(x)   divided by   (x+2)

Step 1: Find a

To find a we will have to convert (x+2) into (x - a) form

i.e.  (x+2) = (x - (-2))

therefore, a = -2

Step 2: Substitute value of a in P(x),

By substitution we get,

2(-2)^{4}+(-2)^{2}-10(-2)-1

= 2(16) + 4 +20 -1

= 32 +4 + 20 - 1

= 55 = Remainder

Hence, Remainder is 55.

8 0
3 years ago
Find the standard form of the equation of the parabola with the given characteristics. Vertex: (-6, 1); focus: (-6, 0)
GREYUIT [131]

Answer: (x+6)^2=-4(y-1)

Step-by-step explanation:

Given

Vertex of the parabola (-6,1)

Focus of the parabola (-6,0)

As the x coordinate of vertex and focus is same and focus lie below the vertex, therefore the parabola is the type of

(x+6)^2=-4a(y-1)

distance between Vertex and focus is 1 unit

\therefore a=1

Parabola becomes

\Rightarrow (x+6)^2=-4(y-1)

8 0
3 years ago
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