Answer:
Step-by-step explanation:
From the problem statement, we can setup the following equation:

where
is the number of months that Rachel has saved up money.
Dividing both sides by 35, we get the answer:

Answer:
The distance between 12m-sides is
.
Step-by-step explanation:
It is given that the parallelogram has sides 10m and 12m and an angle of 45°.
Draw an altitude from one 12m side to another 12 m side as shown in below figure.
The opposite angles of parallelogram are same. Two angles are obtuse angles and two are acute angle.
Since angle C is acute angle therefore it must be 45 degree.








Therefore the distance between 12m-sides is
.
where is the question to this
Answer:
98% Confidencce Interval is ( 3030.6, 7467.4 )
Step-by-step explanation:
Given that:
Sample size
71
Sample size
31
Sample mean
41628
Sample mean
36,379
Population standard deviation
= 4934
Population standard deviation
4180
At 98% confidence interval level, the level of significcance = 1 - 0.98 = 0.02
Critical value at 
The Margin of Error = 
= 
= 
= 
= 2218.40
The Lower limit = 
= ( 41628 - 36379 ) - ( 2218.40)
= 5249 - 2218.40
= 3030.6
The upper limit = 
= ( 41628 - 36379 ) + ( 2218.40)
= 5249 + 2218.40
= 7467.4
∴ 98% Confidencce Interval is ( 3030.6, 7467.4 )
Answer The sample must represent the target population.
Step-by-step explanation: