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Viktor [21]
4 years ago
11

Which expression shows the sum of the polynomials with like terms grouped together? 10x^2y+2xy^2-4x^2-4x^2y

Mathematics
2 answers:
KIM [24]4 years ago
5 0
The answer to the question

USPshnik [31]4 years ago
4 0

Answer:

6x²y+2xy²-4x²

Step-by-step explanation:

Like terms are terms that have the same variables and exponents.

In the given problem, the only like terms are 10x²y and -4x²y; adding these gives us 6x²y.  Bringing down the rest of the terms gives us

6x²y+2xy²-4x²

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3: 3 faces and 4 with the base 4 vertices and 6 edges

Hope this can help you.

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3 years ago
I need help pleaseee​
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If m(x) =x+5/x-1 and n(x) =x-3 which function has the same domain as (m.n)(x)
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Answer:

Step-by-step explanation:

m (x) = (x+ 5) / (x -1)        and     n(x) = x - 3.

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Hence

m(n) = \dfrac{n+5}{n-1}

but n is a function and n = x-3. Now, replace value of n on m (n)

(m(n))= \dfrac{(x-3)+5}{(x-3)-1}

simplify it

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3 years ago
Sara and Paul are on opposite sides of a building that a telephone pole fell on. The pole is leaning away from Paul at
r-ruslan [8.4K]

Answer:

a) See figure attached

b) x = \frac{sin(124)}{sin(34)} 80.086 = 118.732 ft

c) h = 35 sin (59) = 30.0 ft

So then the heigth for the building is approximately 30 ft

Step-by-step explanation:

Part a

We can see the figure attached is a illustration for the problem on this case.

Part b

For this case we can use the sin law to find the value of r first like this:

\frac{sin(22)}{35 ft} =\frac{sin(59)}{r}

r= \frac{sin(59)}{sin(22)} 35 ft = 80.086ft

Then we can use the same law in order to find the valueof x liek this:

\frac{sin(124)}{x ft} =\frac{sin(34)}{80.086}

x = \frac{sin(124)}{sin(34)} 80.086 = 118.732 ft

And that represent the distance between Sara and Paul.

Part c

For this cas we are interested on the height h on the figure attached. We can use the sine indentity in order to find it.

sin (59) = \frac{h}{35}

And if we solve for h we got:

h = 35 sin (59) = 30.0 ft

So then the heigth for the building is approximately 30 ft

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