Answer:
The answer is yes.
Step-by-step explanation:
All you have to do is substitute the y, which is 5, and the x, which is 2, into the equation. When you solve it the answer in the end will be 5=5, which means that point (2,5) does line on that line.
Divide by 5 on both sides and the answer should be m= -5
The question is asking for the amount of minutes Grant can possibly use in a month. So to <span>algebraically express this, the equation, </span>0.10 m+5=$ sums it up.
Step-by-step explanation:
We have:
x - y = 43 , xy = 15
To find, the value of x^2+y^2x
2
+y
2
= ?
∴ x - y = 43
Squaring both sides, we get
(x - y)^2(x−y)
2
= 43^243
2
⇒ x^2+y^2x
2
+y
2
- 2xy = 1849
Using the algebraic identity,
(a - b)^2(a−b)
2
= a^2+b^2a
2
+b
2
- 2ab
⇒ x^2+y^2x
2
+y
2
= 1849 + 2xy
Put xy = 15, we get
x^2+y^2x
2
+y
2
= 1849 + 2(15)
⇒ x^2+y^2x
2
+y
2
= 1849 + 30
⇒ x^2+y^2x
2
+y
2
= 1879
∴ x^2+y^2x
2
+y
2
= 1879
I will send hint follow this hint then slove it .
thankyou
![\bf \stackrel{\textit{multiplying both sides by LCD of 3}}{3(y+5)=3\left[ \cfrac{5}{3}(x-3) \right]}\implies 3y+15=5(x-3) \\\\\\ 3y+15=5x-15\implies -5x+3y=-30\implies \stackrel{\textit{multiplying by -1}}{5x-3y=30}](https://tex.z-dn.net/?f=%5Cbf%20%5Cstackrel%7B%5Ctextit%7Bmultiplying%20both%20sides%20by%20LCD%20of%203%7D%7D%7B3%28y%2B5%29%3D3%5Cleft%5B%20%5Ccfrac%7B5%7D%7B3%7D%28x-3%29%20%5Cright%5D%7D%5Cimplies%203y%2B15%3D5%28x-3%29%0A%5C%5C%5C%5C%5C%5C%0A3y%2B15%3D5x-15%5Cimplies%20-5x%2B3y%3D-30%5Cimplies%20%5Cstackrel%7B%5Ctextit%7Bmultiplying%20by%20-1%7D%7D%7B5x-3y%3D30%7D)
bearing in mind the standard form uses all integers, and the x-variable cannot have a negative coefficient.
