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OLga [1]
3 years ago
7

What is the first numbers of pi?

Mathematics
2 answers:
soldi70 [24.7K]3 years ago
8 0
♥ The first few numbers of pie is known as:
3.141
This is used in several mathematics problems (divide by or multiply by pie (3.141)
kirza4 [7]3 years ago
5 0
3,141......
_____________________________
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Distributive property
GuDViN [60]

Answer:

Distributive property is to divide because the meaning of "distribute" is to divide something or part of something.

Example: 3(4+8) = 36

You have to add the numbers first before multiplying since there are parenthesis. Usually, in the distributive property you will always see parenthesis.

6 0
3 years ago
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Please help!!!! Brainliest worth 15 points
pshichka [43]

Answer:

<em><u>25</u></em><em><u>÷</u></em><em><u>8</u></em><em><u>×</u></em><em><u>9</u></em><em><u>+</u></em><em><u>14</u></em><em><u> </u></em><em><u>/</u></em><em><u>56</u></em><em><u>+</u></em><em><u>6</u></em><em><u> </u></em><em><u>(</u></em><em><u>8</u></em><em><u>×</u></em><em><u>8</u></em><em><u>)</u></em>

5 0
3 years ago
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PLEASE HELP!! which answer is correct??
ad-work [718]
Option( d ) is the correct one.
4 0
3 years ago
I NEED HELP ASAP!<br><br> 7x-3y= 6; х= 3
marysya [2.9K]

Answer:

If you are looking for y it's 5

Step-by-step explanation:

Plug in 3 for x

7(3) -3y = 6

21 - 3y = 6

subtract 21 from both sides

-3y = - 15

divide by three from both sides

y = 5

6 0
3 years ago
7) PG &amp; E have 12 linemen working Tuesdays in Placer County. They work in groups of 8. How many
BabaBlast [244]

Part A

Since order matters, we use the nPr permutation formula

We use n = 12 and r = 8

_{n}P_{r} = \frac{n!}{(n-r)!}\\\\_{12}P_{8} = \frac{12!}{(12-8)!}\\\\_{12}P_{8} = \frac{12!}{4!}\\\\_{12}P_{8} = \frac{12*11*10*9*8*7*6*5*4*3*2*1}{4*3*2*1}\\\\_{12}P_{8} = \frac{479,001,600}{24}\\\\_{12}P_{8} = 19,958,400\\\\

There are a little under 20 million different permutations.

<h3>Answer: 19,958,400</h3>

Side note: your teacher may not want you to type in the commas

============================================================

Part B

In this case, order doesn't matter. We could use the nCr combination formula like so.

_{n}C_{r} = \frac{n!}{r!(n-r)!}\\\\_{12}C_{8} = \frac{12!}{8!(12-8)!}\\\\_{12}C_{8} = \frac{12!}{4!}\\\\_{12}C_{8} = \frac{12*11*10*9*8!}{8!*4!}\\\\_{12}C_{8} = \frac{12*11*10*9}{4!} \ \text{ ... pair of 8! terms cancel}\\\\_{12}C_{8} = \frac{12*11*10*9}{4*3*2*1}\\\\_{12}C_{8} = \frac{11880}{24}\\\\_{12}C_{8} = 495\\\\

We have a much smaller number compared to last time because order isn't important. Consider a group of 3 people {A,B,C} and this group is identical to {C,B,A}. This idea applies to groups of any number.

-----------------

Another way we can compute the answer is to use the result from part A.

Recall that:

nCr = (nPr)/(r!)

If we know the permutation value, we simply divide by r! to get the combination value. In this case, we divide by r! = 8! = 8*7*6*5*4*3*2*1 = 40,320

So,

_{n}C_{r} = \frac{_{n}P_{r}}{r!}\\\\_{12}C_{8} = \frac{_{12}P_{8}}{8!}\\\\_{12}C_{8} = \frac{19,958,400}{40,320}\\\\_{12}C_{8} = 495\\\\

Not only is this shortcut fairly handy, but it's also interesting to see how the concepts of combinations and permutations connect to one another.

-----------------

<h3>Answer: 495</h3>
5 0
3 years ago
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