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3 years ago

14

Two cars leave the same parking lot, with one heading south and the other heading east. After several minutes, the southbound ca

r has traveled 15 miles, and the eastbound car has traveled 20 miles. Measured in a straight line, how far apart are the two cars?

1 answer:

ELEN [110]3 years ago

6 0

Answer:

25

Step-by-step explanation:

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8 ft wide, 12 ft long......so if u want it 2 ft wide, u have a scale factor of 1/4.
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daser333 [38]

Answer:

x = $\frac{1}{5}$ , y = 6

Step-by-step explanation:

5x + y = 7 → (1)

20x + 2 = y → (2)

Substitute y = 20x + 2 into (1)

5x + 20x + 2 = 7

25x + 2 = 7 ( subtract 2 from both sides )

25x = 5 ( divide both sides by 25 )

x = $\frac{5}{25}$ = $\frac{1}{5}$

Substitute this value into (2) and evaluate

20( $\frac{1}{5}$ ) + 2 = y

4 + 2 = y , so

y = 6

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3 years ago

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Find the solution set of the absolute value equation: |2x−6|+4=20

vekshin1

$|2x - 6| = 16 \\ 2x - 6 = 16 > > > x = \frac{22}{2} = 11 \\ 2x - 6 = - 16 > > x = - 5$

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C is 8 more than half than n

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$\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ (\stackrel{x_1}{-4}~,~\stackrel{y_1}{-7})\qquad (\stackrel{x_2}{-2}~,~\stackrel{y_2}{-5})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ \stackrel{diameter}{d}=\sqrt{[-2-(-4)]^2+[-5-(-7)]^2}\implies d=\sqrt{(-2+4)^2+(-5+7)^2} \\\\\\ d=\sqrt{2^2+2^2}\implies d=\sqrt{2\cdot 2^2}\implies d=2\sqrt{2}~\hfill \stackrel{~\hfill radius}{\cfrac{2\sqrt{2}}{2}\implies\boxed{ \sqrt{2}}} \\\\[-0.35em] ~\dotfill$

$\bf ~~~~~~~~~~~~\textit{middle point of 2 points } \\\\ (\stackrel{x_1}{-4}~,~\stackrel{y_1}{-7})\qquad (\stackrel{x_2}{-2}~,~\stackrel{y_2}{-5})\qquad \qquad \qquad \left(\cfrac{ x_2 + x_1}{2}~~~ ,~~~ \cfrac{ y_2 + y_1}{2} \right) \\\\\\ \left( \cfrac{-2-4}{2}~~,~~\cfrac{-5-7}{2} \right)\implies \left( \cfrac{-6}{2}~,~\cfrac{-12}{2} \right)\implies \stackrel{center}{\boxed{(-3,-6)}} \\\\[-0.35em] ~\dotfill$

$\bf \textit{equation of a circle}\\\\ (x- h)^2+(y- k)^2= r^2 \qquad center~~(\stackrel{-3}{ h},\stackrel{-6}{ k})\qquad \qquad radius=\stackrel{\sqrt{2}}{ r} \\[2em] [x-(-3)]^2+[y-(-6)]^2=(\sqrt{2})^2\implies (x+3)^2+(y+6)^2=2$

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3 years ago

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