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cupoosta [38]
3 years ago
15

Which sets of values belong to the domain and range of a relation?

Mathematics
2 answers:
Nimfa-mama [501]3 years ago
4 0

Answer:

Domain: input values, independent variables

Range: output vales, dependent variables

Step-by-step explanation:

Think of it like a graph: the domain are the x-values and the range is the y-values. if you're doing a problem with time, the time will go on the x-axis and cannot be influenced by the y-values, but the y-vales are depending on what the x-values are (independent/dependent). for the input/output, usually when solving equations on a graph, you plug in the x-value and find the y-value. you're INPUTTING the x-value to receive the OUPUT.

Vikentia [17]3 years ago
3 0

Domain = set of allowed inputs

The input x is the independent variable as it can do whatever it wants without relying on y.

-------------------------

Range = set of possible outputs

The output is the dependent variable. It depends on what the input x is. Often, we make y the output dependent variable.

-------------------------

For example, with y = 2x+5, we can plug in anything we want for x (it doesn't need to look to y for guidance or anything). Once we pick something for x, it will directly determine what y is.

Let's say we picked x = 10. That would mean y = 2x+5 = 2*10+5 = 25. The input x = 10 in the domain leads to y = 25 in the range. We see that the output y = 25 depends entirely on the independent input x = 10.

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Help please! (no one was answering it in physics and i really need help)
aivan3 [116]

Let v_0 be the cat's speed just as it leaves the edge of the table. Then taking the point 1.3 m below the edge of the table to be the origin, the cat's horizontal position at time t is given by

x(t)=v_0t

and its height is

y(t)=1.3\,\mathrm m-gt^2

where g is 9.8 m/s^2, the magnitude of the acceleration due to gravity.

The time it takes for the cat to hit the ground is t with

0=1.3\,\mathrm m-gt^2\implies t=\sqrt{\dfrac{1.3\,\rm m}g}\approx0.36\,\mathrm s

(Unfortunately, this doesn't match any of the given options...)

The cat lands 0.75 m away (horizontally) from the edge of the table, so that its speed v_0 was

0.75\,\mathrm m=v_0(0.36\,\mathrm s)\implies v_0\approx2.08\dfrac{\rm m}{\rm s}

(Again, not one of the answer choices...)

I'm guessing there's either a typo in the question or answers.

6 0
3 years ago
Subtract.<br> (6x + 5) - (x + 3)<br> A. 5x + 2<br> B. 6x + 2<br> C! 6x + 8<br> D. 5x + 8
Natali [406]

Answer: 5x + 2

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Can someone please help? what is the missing length?
Harrizon [31]
31

since A = 1/2 b h, and the A is 279 and the height is 18, we can plug them in and solve for b.
8 0
3 years ago
Or lingneeds 2 yards of fabric for a raft project .she has 3 feet already. how many inches of fabric that she need still need?
otez555 [7]
2 yards = 72 inches
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72 - 36 = 36
She still needs 36 inches of fabric.
7 0
3 years ago
Give an example of a rational function that has a horizontal asymptote of y = 2/9.
stiv31 [10]
Note that the graph of the function \displaystyle{ f(x)= \frac{1}{x} has 2 asymptotes:

The horizontal asymptote x=0, 

and the vertical asymptote y=0, as shown in the first picture.


Adding 2/9 to this function, creating \displaystyle{ g(x)= \frac{1}{x}+\frac{2}{9}, shifts the first graph 2/9 units up. It also shifts the horizontal asymptote y=0 to t=2/9.

We can express the function as \displaystyle{ \frac{1}{x}+ \frac{2}{9}= \frac{9}{9x}+ \frac{2x}{9x}= \frac{2x+9}{9x}.


Answer: \displaystyle{ \frac{2x+9}{9x}


4 0
3 years ago
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