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lianna [129]
2 years ago
9

Find the perimeter of the figure to the nearest hundredth. (I’ll mark brainliest if correct)

Mathematics
2 answers:
Lady bird [3.3K]2 years ago
3 0

20

Step-by-step explanation:

ajdudjsndjbsjsbehsbd

Gala2k [10]2 years ago
3 0
48.57

EXPLANATION

6(6) = 36 (square)

two semi circles = circle
circumference of circle is 2(pi)(r)

C = 2(3.14)(2)
C = 12.57

Perimeter = 12.57 + 36
= 48.57
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I need help! Please help me and tell me how you got the answer. Will mark brainlist!
Serggg [28]

Answer:

3. <em>V= 192</em>

4. <em>V= 32</em>

Step-by-step explanation:

first, <u>find</u> the area of the base by multiplying length by width.

Once you <u>determine</u> the area of the base, multiply that by height

6 0
2 years ago
Read 2 more answers
Solve the integral:<br><img src="https://tex.z-dn.net/?f=%20%5Cint%20%5C%3A%20%20%7Be%7D%5E%7B%20-%20%20%7Bx%7D%5E%7B2%7D%20%7D%
Sever21 [200]

e^{-x^2} has no antiderivative in terms of elementary functions (polynomials, exponentials, logarithms, trigonometric functions, etc), but there is a special function defined to fit that role called the error function, \mathrm{erf}(x), where

\mathrm{erf}(x)=\displaystyle\frac2{\sqrt\pi}\int_0^xe^{-t^2}\,\mathrm dt

By the fundamental theorem of calculus, we can see that

\dfrac{\mathrm d}{\mathrm dx}\mathrm{erf}(x)=\dfrac2{\sqrt\pi}e^{-x^2}

which means we have

\displaystyle\int e^{-x^2}\,\mathrm dx=\dfrac{\sqrt\pi}2\mathrm{erf}(x)+C

8 0
3 years ago
Write as a decimal -3/5 show the work
faltersainse [42]
-3/5
-6/10
-.06 is the answer
3 0
2 years ago
Write the quadratic function in standard form.<br> f(x) = -x2 + 2x + 4<br> f(x) =
goldenfox [79]

Answer:

f(x)=-1(x-2)^2+8

Step-by-step explanation:

Given:

The quadratic function is given as:

f(x)=-x^2+2x+4

The standard form of a quadratic function is given as:

f(x)=a(x-h)^2+k, where, 'a', 'h' and 'k' are real numbers.

Now, in order to convert the given function to standard form, we use completing by  square method.

-x^2+2x=-(x^2-2x)=-[(x-2)^2-2^2]=-[(x-2)^2-4]=-(x-2)^2+4

Now, f(x)=-x^2+2x+4 can be rewritten as:

f(x)=-(x-2)^2+4+4\\f(x)=-1(x-2)^2+8

Therefore, the standard form of the function is:

f(x)=-1(x-2)^2+8

7 0
2 years ago
What is the answer needdd it
Naddik [55]
I think it would be b or c
3 0
3 years ago
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