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QveST [7]
3 years ago
14

5.Find the domain of the following function:

Mathematics
2 answers:
Vladimir79 [104]3 years ago
3 0

Answer:

(-∞,∞)

B) x cannot equal -4, 2

Step-by-step Explanation:

The function, y = x + 2, has a domain of (-∞,∞) because the equation will remain true no matter number you plug for x.

For the second question, x would be equal to -2 and 4.  You can find this by factoring the equation.  x² + 2x - 8 = (x - 2)(x + 4)  Your answer should be B

vichka [17]3 years ago
3 0

Answer:

B) x cannot equal −4, 2

Step-by-step explanation:

x² + 2x - 8 = 0

When x = -4, 2

When the denominator becomes zero, function becomes undefined

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I have to get this so I pass help plz
pshichka [43]

Answer:

\boxed{\sf x=-2}

\boxed{\sf y=-4}

Step-by-step explanation:

<u>First, Let's  solve for x in -2x+2y=-4:</u>

\sf -2x+2y=-4

<u>Subtract 2y from both sides:</u>

\sf -2x+2y-2y=-4-2y

\sf -2x=-4-2y

<u>Divide both sides by -2:</u>

\sf \cfrac{-2x}{-2}=-\cfrac{4}{-2}-\cfrac{2y}{-2}

\bold{ x=y+2}

<u>Now, we'll substitute x=y+2 to 3x+3y=-18:</u>

\sf 3x+3y=-18

→ let x=2+y

\sf 3\bold{(2+y)}+3y=-18

<u>Simplify:</u>

\sf 6+6y=-18

<u>Now, let's solve for y in 6+6y=-18</u>

\sf 6+6y=-18

<u>Subtract 6 from both sides:</u>

\sf 6+6y-6=-18-6

\sf 6y=-24

<u>Divide both sides by 6:</u>

\sf \cfrac{6y}{6}=\cfrac{-24}{6}

\bold{ y=-4}

<u>Now, substitute y=-4 into x=2+y:</u>

\sf x=2+y

→ let y = -4

\sf x=2+\bold{-4}

\bold{x=-2}

Therefore, x=-2 and y=-4.

<u>_____________________________________</u>

5 0
2 years ago
Sammy usually takes a 18 minute shower in the morning. If a 4 minute shower uses an average of 20-40 gallons of water, what is t
mylen [45]
D 180 gallons of water
5 0
3 years ago
Read 2 more answers
$$ \sqrt{6\frac{1}{4}} $$
ratelena [41]
Chu gf fr uvv V dhh gg jb cub
6 0
3 years ago
PLEASE HELP THIS IS EASY BUT IM JUST BAD AT MATH
balandron [24]

Answer:

Its B

Step-by-step explanation:

Try and read throught it slowly and everytime you hit a variable go down the the answer and find where it is. That helped me a lot

5 0
2 years ago
Read 2 more answers
Two quadratic functions are shown.
slava [35]

Answer:

Option (1) is the correct option.

Step-by-step explanation:

Function 1,

f(x) = 4x² + 8x + 1

     = 4(x² + 2x) + 1

     = 4(x² + 2x + 1 - 1) + 1

     = 4(x² + 2x + 1) - 4 + 1

f(x) = 4(x + 1)² - 3

This graph opens up with the vertex or minimum point at (-1, -3)

So, the minimum value of the function is (-3) at x = -1.

Function (2)

From the given table minimum value of the function is 0 at x = -1 or minimum point as (-1, 0)

Therefore, Function 1 has the least minimum value and its coordinates are (-1, -3)

Option (1) is the correct option.

7 0
2 years ago
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