No
Mark brainliest please
Hope this helps you
Answer:
![\displaystyle \sin(D)=\frac{28}{53}\approx0.5283](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Csin%28D%29%3D%5Cfrac%7B28%7D%7B53%7D%5Capprox0.5283)
![\displaystyle \sin(E)=\frac{45}{53}\approx0.8491](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Csin%28E%29%3D%5Cfrac%7B45%7D%7B53%7D%5Capprox0.8491)
Step-by-step explanation:
Remember that sine is the ratio of the opposite side to its hypotenuse:
![\displaystyle \sin(x^\circ)=\frac{\text{Opposite}}{\text{Hypotenuse}}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Csin%28x%5E%5Ccirc%29%3D%5Cfrac%7B%5Ctext%7BOpposite%7D%7D%7B%5Ctext%7BHypotenuse%7D%7D)
For D, the opposite side to D is 28, and the hypotenuse is 53. Therefore:
![\displaystyle \sin(D)=\frac{28}{53}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Csin%28D%29%3D%5Cfrac%7B28%7D%7B53%7D)
Or, in decimal form:
![\sin(D)\approx 0.5283](https://tex.z-dn.net/?f=%5Csin%28D%29%5Capprox%200.5283)
Likewise, the side opposite to E is 45, and the hypotenuse is 53. Therefore:
![\displaystyle \sin(E)=\frac{45}{53}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Csin%28E%29%3D%5Cfrac%7B45%7D%7B53%7D)
And using a calculator:
![\sin(E)\approx0.8491](https://tex.z-dn.net/?f=%5Csin%28E%29%5Capprox0.8491)
Answer:
H
Step-by-step explanation:
3:2 IS EQUAL TO 3/2
Answer:
151 in^3
Step-by-step explanation:
The rocket consists of two shapes - a cone and a cylinder
the volume of the plastic = volume of cone + volume of cylinder
volume of a cylinder = nr^2h
Volume of a cone 1/3(nr^2h)
n = 22/7
r = radius
the diameter is the straight line that passes through the center of a circle and touches the two edges of the circle.
A radius is half of the diameter
Radius = 5/2 = 2.5
Height of cone = 11 - 6 = 5
Volume of plastic = (22/7) x (2/5^2) x 6 + (1/3) x (22/7) x (2/5^2) x 5 = 117.9 + 32.7 = 150.6 in^3 = 151
Answer:
A, B and C
Step-by-step explanation:
Given any three side lengths of a right triangle, the longest side is the hypotenuse.
The side lengths of a right triangle must satisfy the <u>Pythagorean Theorem. </u>
Pythagorean Theorem: ![Hypotenuse^2=Opposite^2+Adjacent^2](https://tex.z-dn.net/?f=Hypotenuse%5E2%3DOpposite%5E2%2BAdjacent%5E2)
<u>Option A:</u> ![3, 6, \sqrt{45}](https://tex.z-dn.net/?f=3%2C%206%2C%20%5Csqrt%7B45%7D)
![(\sqrt{45})^2=3^2+6^2\\45=36+9\\45=45](https://tex.z-dn.net/?f=%28%5Csqrt%7B45%7D%29%5E2%3D3%5E2%2B6%5E2%5C%5C45%3D36%2B9%5C%5C45%3D45)
True
<u>Option B:</u> 2.5, 6, 6.5
![6.5^2=6^2+2.5^2\\42.25=36+6.25\\42.25=42.25 (TRUE)](https://tex.z-dn.net/?f=6.5%5E2%3D6%5E2%2B2.5%5E2%5C%5C42.25%3D36%2B6.25%5C%5C42.25%3D42.25%20%28TRUE%29)
<u>Option C:</u> ![4, 8, \sqrt{80}](https://tex.z-dn.net/?f=4%2C%208%2C%20%5Csqrt%7B80%7D)
![4, 8, \sqrt{80}\\( \sqrt{80})^2=4^2+8^2\\80=16+64\\80=80 (TRUE)](https://tex.z-dn.net/?f=4%2C%208%2C%20%5Csqrt%7B80%7D%5C%5C%28%20%5Csqrt%7B80%7D%29%5E2%3D4%5E2%2B8%5E2%5C%5C80%3D16%2B64%5C%5C80%3D80%20%28TRUE%29)
Since all are true, the side lengths in Options A, B and C forms a right triangle,