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Studentka2010 [4]
3 years ago
8

I don't get the subject of congruent triangles. How do I figure out if there's not enough information to know if it is congruent

? Also, how do you do a flow chart? Thanks!!​
Mathematics
1 answer:
babymother [125]3 years ago
5 0

Answer:

Okay, there are many ways to find if a triangle is congruent.

Let's start with some different terminology.

For the sake of simplicity let us say that S stands for when a side is congruent for both triangles and A stands for when an angle (<) is congruent between both the triangles as well.

So, you need to memorize some rules. If you find that 2 triangles are congruent in the sense of; SSS, SAS, AAS, SAA, and ASA. One thing to remember is that Angle Side Side isn't congruent and is called <em>Donkey Theorem</em>. This theorem only works for right triangles.

One way to know if your triangle isn't congruent is if you can find a part of the triangle that is different.

I know that wasn't the best explanation but I hope it helped anyhow. :)

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Step-by-step explanation:

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By Pythagoras theorem, we have;

{\overline {R'Q'} }^2 = {\overline {R'S'} }^2 + {\overline {S'Q'} }^2

Therefore;

{\overline {R'S'} }^2  = {\overline {R'Q'} }^2  - {\overline {S'Q'} }^2 = \left ({3 \times \overline {RQ} } \right) ^2  - \left (3 \times {\overline {SQ} } \right) ^2 = 9 \times \left (\overline {RQ} }  ^2  -  {\overline {SQ} } ^2 \right) = 9 \times  {\overline {RS} }^2

\therefore \sqrt{  {\overline {R'S'} }^2} =  \sqrt{ 9 \times  {\overline {RS} }^2}= 3 \times  {\overline {RS} }

\overline {R'S'}  = 3 \times  {\overline {RS} }.

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