When two triangles are congruent they will have exactly the same three sides and exactly the same three angles. The equal sides and angles may not be in the same position (if there is a turn or a flip), but they are there.

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A line contains the points R (-1, 8) S (1, 4) and T (6, y). Solve for y. Be sure to show and explain all work.

Nikitich [7]

Given:

A line contains the points R(-1, 8), S(1, 4) and T(6, y).

To find:

The value of y.

Solution:

Three points are collinear if:

$x_1(y_2-y_3)+x_2(y_3-y_2)+x_3(y_1-y_2)=0$

A line contains the points R(-1, 8), S(1, 4) and T(6, y). It means, these points are collinear.

$-1(4-y)+1(y-8)+6(8-4)=0$

$-4+y+y-8+48-24=0$

$2y+12=0$

Subtract 12 from both sides.

$2y=-12$

Divide both sides by 2.

$y=\dfrac{-12}{2}$

$y=-6$

Therefore, the value of y is -6.

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3 years ago