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2 years ago

Jake says the 3 in 738 has a value of 3. He shows

Mathematics

1 answer:

NeX [460]2 years ago

3 0

No because the 3 is the tens place. So its supposed to 3 ten blocks

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Part 1

natali 33 [55]

Because December is really cold

5 0

2 years ago

Which expression is equivalent to (4x^(3)y^(5))(3x^(5)y)^(2)

marshall27 [118]

Answer:

$(4x^3y^5)(3x^5y)^2 = 36*x^{13}y^7$

Step-by-step explanation:

Given

$(4x^3y^5)(3x^5y)^2$

Required

The equivalent expression

We have:

$(4x^3y^5)(3x^5y)^2$

Expand

$(4x^3y^5)(3x^5y)^2 = 4x^3y^5*9x^{10}y^2$

Further expand

$(4x^3y^5)(3x^5y)^2 = 4*9*x^3*x^{10}y^5*y^2$

Apply laws of indices

$(4x^3y^5)(3x^5y)^2 = 36*x^{13}y^7$

8 0

3 years ago

X^2-6x+5=0 solve with quadratic formula

Yuliya22 [10]

Answer: x1 = 5

x2 = 1

Step-by-step explanation:

1. Identify the coefficients

2. Move the constant to the right side of the equation and combine

3. Complete the square

4. Solve for x

7 0

1 year ago

Read 2 more answers

35% of the students in a school of 2060 are freshmen. How many students in the school are freshmen

Svetllana [295]

There are 721 freshman.
Make 35% a decimal, multiply by 2060
.35*2060=721

5 0

2 years ago

Read 2 more answers

Can you guys help me out on this? I'm still learning sign, cosign, and tangent :)

Yakvenalex [24]

Answer:

$\sin d = \frac{4}{7}$ ; $\sin e = \frac{\sqrt{33} }{7}$

$\cos d = \frac{\sqrt{33} }{7}$ ; $\cos e = \frac{4}{7}$

$\tan d = \frac{4}{\sqrt{33} }$ ; $\tan e = \frac{\sqrt{33} }{4}$

Step-by-step explanation:

For a right angled triangle with one of its angle α (alpha) :-

$\sin \alpha = \frac{Side \: opposite \: to \: \alpha }{Hypotenuse \: of \: the \: triangle}$

$\cos \alpha = \frac{Side \: adjacent \: to \: \alpha }{Hypotenuse \: of \: the \: triangle}$

$\tan \alpha = \frac{Side \: opposite \: to \: \alpha }{Side \: adjacent \: to \: \alpha }$

__________________________________________________

According to the question ,

1) When α (alpha) = d

$\sin d = \frac{4}{7}$

$\cos d = \frac{\sqrt{33} }{7}$

$\tan d = \frac{4}{\sqrt{33} }$

2) When α (alpha) = e

$\sin e = \frac{\sqrt{33} }{7}$

$\cos e = \frac{4}{7}$

$\tan e = \frac{\sqrt{33} }{4}$

3 0

2 years ago