Answer:
Explanation:
The resulting valie would be too large
Answer:
a) F = 680 N, b) W = 215 .4 J
, c) F = 1278.4 N
Explanation:
a) Hooke's law is
F = k x
To find the displacement (x) let's use the elastic energy equation
= ½ k x²
k = 2
/ x²
k = 2 85.0 / 0.250²
k = 2720 N / m
We replace and look for elastic force
F = 2720 0.250
F = 680 N
b) The definition of work is
W = ΔEm
W =
- 
W = ½ k (
² - x₀²)
The final distance
= 0.250 +0.220
= 0.4750 m
We calculate the work
W = ½ 2720 (0.47² - 0.25²)
W = 215 .4 J
We calculate the strength
F = k 
F = 2720 0.470
F = 1278.4 N
You use less energy to provide the same service.
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Answer:600N/m
Explanation: Given ;
Applied force(F) = 180N
Total extension (l) = 30cm =0.30m
Spring constant(K) =?
From Hooke's law
F= kx
therefore k= F/x
k = 180N/0.3m
600N/m