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3 years ago

Which of the following describe a neutron?

Physics

1 answer:

Leokris [45]3 years ago

5 0

Neutral charge, because neutron means neutral

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How does a sound wave transfer energy to your ears ?

KiRa [710]

It transfers energy through the source of the sound. Your ear detects sound waves when vibrating air particles cause your ear drum to vibrate

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3 years ago

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2 Points

Mademuasel [1]

According to Newton's Second Law of Motion :

The Force acting on an Object is equal to Product of Mass of the Object and Acceleration produced due to the Force.

$:\implies$ Force acting = Mass of the Object × Acceleration

Given : Force = 50 newton and Mass of the Object = 10 kg

Substituting the respective values in the Formula, we get :

$:\implies$ 50 N = 10 kg × Acceleration

$:\implies \mathsf{Acceleration = \dfrac{50\;N}{10\;kg}}$

$:\implies$ Acceleration of the Object = 5 m/s²

4 0

3 years ago

Fronts are termed by the temperature of the air mass that overtakes another air mass. A. True B. False

Vikki [24]

A. True
if cold air is replacing warm air it is a cold front and vice versa.

6 0

2 years ago

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The maximum distance which our normal eye can see distinctly is known as _______________

azamat

Answer:

Far point.

Explanation:

The maximum distance up to which the normal eye can see objects distinct and clear is called the far point of the eye. It is infinity for a normal eye.

7 0

2 years ago

Unpolarized light with intensity 300 W/m^2 passes first through a polarizing filter with its axis vertical, then through a secon

SOVA2 [1]

Answer:

The angle from vertical of the axis of the second polarizing filter is 50.57⁰.

Explanation:

Given;

intensity of the unpolarized light, I₀ = 300 W/m²

intensity of emergent polarized light, I = 121 W/m²

let the angle from vertical of the axis of the second polarizing filter = θ

Apply Malus's law, intensity of emergent polarized light is given as;

I = I₀Cos²θ

$Cos^2 \theta = \frac{I}{I_o} \\\\Cos^2 \theta =\frac{121}{300} \\\\Cos^2 \theta =0.4033\\\\Cos \theta = \sqrt{0.4033} \\\\Cos \theta = 0.6351\\\\\theta = Cos^{-1} (0.6351)\\\\\theta = 50.57 ^0$

Therefore, the angle from vertical of the axis of the second polarizing filter is 50.57⁰.

8 0

2 years ago