Question

If a net force of 34.3 N is required to move the system in the figure to the right 2.3 m in 1.3 seconds what is the systems mass

Answer 1

Mass of the system is 25.2 kg
Calculation:

F=ma

m = F/a  where a = m/t^2

a=2.3/(1.3)^2 = 1.36 m/s^2

m=34.3/1.36

m=25.2 Kg

Answer 2

Answer:

m = 12.6 kg

Explanation:

As we know that it covers total distance of 2.3 m in 1.3 s

so we will have

$v_i = 0$

$d = 2.3 m$

$t = 1.3 s$

now we can use kinematics to find the acceleration

$d = v_i t + \frac{1}{2}at^2$

$2.3 = \frac{1}{2}a(1.3^2)$

$a = 2.72 m/s^2$

Now we can use Newton's law

$F = ma$

$34.3 = m(2.72)$

$m = 12.6 kg$