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Serga [27]
3 years ago
6

A source charge generates an electric field of 1236 N/C at a distance of 4 m. What is the magnitude of the source charge?

Physics
1 answer:
Lera25 [3.4K]3 years ago
4 0

Answer:

A. 2.2 ɥC

Explanation:

Given;

electric field strength, E = 1236 N/C

distance of the source charge, r = 4 m

Electric field strength is calculated as;

E = \frac{kQ}{r^2}

where;

Q is the magnitude of the source charge

k is Coulomb's constant = 9 x 10⁹ Nm²/C²

E = \frac{kQ}{r^2} \\\\kQ = Er^2\\\\Q = \frac{Er^2}{k} \\\\Q = \frac{(1236)(4^2)}{9 \ \times \ 10^9} \\\\Q = 2.197 \ \times \ 10^{-6} \ C\\\\Q = 2.197 \ \mu \ C

Therefore, the correct option is A. 2.2 ɥC

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Answer: Force F will be one-sixteenth of the new force when the charges are doubled and distance halved

Explanation:

Let the charges be q1 and q2 and the distance between the charges be 'd'

Mathematical representation of coulombs law will be;

F1=kq1q2/d²...(1)

Where k is the electrostatic constant.

If q1 and q2 is doubled and the distance halved, we will have;

F2 = k(2q1)(2q2)/(d/2)²

F2 = 4kq1q2/(d²/4)

F2 = 16kq1q2/d²...(2)

Dividing equation 1 by 2

F1/F2 = kq1q2/d² ÷ 16kq1q2/d²

F1/F2 = kq1q2/d² × d²/16kq1q2

F1/F2 = 1/16

F1 = 1/16F2

This shows that the force F will be one-sixteenth of the new force when the charges are doubled and distance halved

4 0
3 years ago
Which of the following is an example of deposition?
Murrr4er [49]
 B would be the correct answer 
4 0
3 years ago
a plane travels 204 km, northeast in 15.0 minutes. It also increases elevation by 1.6 km, upward in the same amount of time. Wha
LUCKY_DIMON [66]

Answer:

230 m/s northeast, 1.8 m/s up

Explanation:

204 kilometres = 204000 metres

15.0 minutes = 900 seconds

Velocity = Distance / Time

= 204000 / 900

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1.6km = 1600 metres

Velocity = 1600 / 900

= 1.8 m/s up (to 2 sf.)

Read more on Brainly.com - brainly.com/question/13863590#readmore

5 0
3 years ago
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Answer:

Explanation:

net force on the skier = mg sin 39 - μ mg cos39

mg ( sin39 - μ cos39 )

= 73 x 9.8 ( .629 - .116)

= 367 N

impulse = net force x time = change in momentum .

= 367 x 5 = 1835 kg m /s

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b )

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c )

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so he will have speed of 25.13 m /s after 5 s .

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3 years ago
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