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2 years ago

A source charge generates an electric field of 1236 N/C at a distance of 4 m. What is the magnitude of the source charge?

Physics

1 answer:

Lera25 [3.4K]2 years ago

4 0

Answer:

A. 2.2 ɥC

Explanation:

Given;

electric field strength, E = 1236 N/C

distance of the source charge, r = 4 m

Electric field strength is calculated as;

$E = \frac{kQ}{r^2}$

where;

Q is the magnitude of the source charge

k is Coulomb's constant = 9 x 10⁹ Nm²/C²

$E = \frac{kQ}{r^2} \\\\kQ = Er^2\\\\Q = \frac{Er^2}{k} \\\\Q = \frac{(1236)(4^2)}{9 \ \times \ 10^9} \\\\Q = 2.197 \ \times \ 10^{-6} \ C\\\\Q = 2.197 \ \mu \ C$

Therefore, the correct option is A. 2.2 ɥC

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