Answer:
Your answers are correct!!! I just cant see the top as i told u in the details place....
Please brainlest...
Step-by-step explanation:
James will need 115.08mg of medicine at the start of day 6.
Since in a pass code, the placement of the digits is
important, therefore this means that to solve for the total number of
possibilities we have to make use of the principle of Permutation. The formula
for calculating the total number of possibilities using Permutation is given
as:
P = n! / (n – r)!
where,
n = is the total amount of numbers to choose from = 20
r = is the total number of digits needed in the passcode =
4
Therefore solving for the total possibilities P:
P = 20! / (20 – 4)!
P = 20! / 16!
P = 116,280
<span>Hence there are a total of 116,280 possibilities of pass
codes.</span>
Answer:
- f(1) = 4
- f(n) = f(n - 1) + 4
Step-by-step explanation:
Given the sequence:
The first term is 4 and common difference is 4
<u>Recursive formula:</u>
- f(1) = 4
- f(n) = f(n - 1) + 4
To round off decimals:
Find the place value you want (the "rounding digit") and look at the digit just to the right of it.
If that digit is less than 5, do not change the rounding digit but drop all digits to the right of it.
If that digit is greater than or equal to five, add one to the rounding digit and drop all digits to the right of it.
To round off whole numbers:
Find the place value you want (the "rounding digit") and look to the digit just to the right of it.
If that digit is less than 5, do not change the "rounding digit" but change all digits to the right of the "rounding digit" to zero.
If that digit is greater than or equal to 5, add one to the rounding digit and change all digits to the right