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Nostrana [21]
3 years ago
5

In a “Fibonacci” sequence of numbers, each term beginning with the third, is the sum of the previous two terms. The first number

in such a sequence is 2 and the third is 9. What is the eighth term in the sequence?
Mathematics
1 answer:
Fed [463]3 years ago
6 0

Answer:

<em><u>8</u></em><em><u>t</u></em><em><u>h</u></em><em><u> </u></em><em><u>t</u></em><em><u>e</u></em><em><u>r</u></em><em><u>m</u></em><em><u>=</u></em><em><u>1</u></em><em><u>0</u></em><em><u>7</u></em>

Step-by-step explanation:

Here the sequence is following the 'fibonacci's sequence of numbers.....

i.e,Tn=T(n-1) +T(n-2), where n>2 but this sequence is not fibonnaci's number , it's not starting with 0, 1,1,2........

so you cannot apply formula to calculate,you have to find 8th term by simple calculation.....

Like here 3rd term is 9 and 1st term is 2

now 3rd term = 2nd term+1st term (sum of previous two terms)

i.e, 9= 2nd term +2

i.e, 2nd term =7

now, 4th term = 3rd +2nd

= 9+7=<u>1</u><u>6</u>

<u>again</u><u>,</u><u> </u> 5th term = 4th +3rd

=16+9=25

again,6th term =5th+4th

=25+16=41

again,7th term=6th+5th

=41+25=66

again,8th term=7th+6th

=66+41=107

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