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miskamm [114]
3 years ago
5

Solve the equation for 'C' B + C = -D ​

Mathematics
1 answer:
vlabodo [156]3 years ago
5 0

Answer:

C = -D - B

Step-by-step explanation:

Step 1: Write out equation

B + C = -D

Step 2: Subtract B on both sides

C = -D - B

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A scientist has discovered an organism that replicates at a rate of five per hour and lives for one week. Each replicated organi
bezimeni [28]
A)2,801 

write an equation for the translation of y= [x]. 16.5 units
4 0
4 years ago
The pole casts a 12-foot shadow when the sun is at a 40° angle of elevation. Which equation could Kim use to find x, the length
bonufazy [111]

Answer    

Find out the length of the pole .

To proof

As given

The pole casts a 12-foot shadow when the sun is at a 40° angle of elevation.

x represented the length of pole .

As shown in the diagram

By using the trignometric identity

tan \theta = \frac{Perpendicular}{Base}

tan 40^{\circ} = \frac{x}{12}

tan40° = 0.839099631 ( approx )

Put in the above

x = 12 × 0.839099631

x = 10.1 foot (approx)

Therefore the  length of the pole in  10.1 foot (approx) .



     

4 0
3 years ago
Given WX II ZY, and ZZ = XX. Prove AWXY-AYZW.<br> PLEASE HELP!!
Andrej [43]

Answer:

WX // ZY > GIVEN

WX~ZY (SIDE) > PARALLEL LINES ARE CONGRUENT

<Z~<X (ANGLE) > GIVEN

WY~WY (SIDE) > REFLEXIVE PROPERTY OF CONGRUENCE

TRIANGLE WXY ~ TRIANGLE YZW > SAS

8 0
3 years ago
Find the slant height of a right circular cone with a radius of 3 and a height of 5?
Ivahew [28]
Check the picture below.

6 0
4 years ago
WILL GIVE BRAINLIEST!
yKpoI14uk [10]

Answer:

50 A and 50 B

Step-by-step explanation:

A》20

B》10

A + B》100 (for pants)

A + 3B》200 (for shirts)

A = 20

A + 3B = 200

3B = 180

B = 60

(20,60)

B = 10

A + B = 100

A = 90

(90,10)

A + B = 100

A = 100 - B

A + 3B = 200

100 - B + 3B = 200

2B = 100

B = 50

A = 100 - 50 = 50

(50,50)

Revenue:

30A + 50B

(20,10): 30(20) + 50(20)

= 1,100

(20, 60): 30(20) + 50(60)

= 3,600

(90,10): 30(90) + 50(10)

= 3,200

(50,50): 30(50) + 50(50)

= 4,000

8 0
3 years ago
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