Those are all lines...
So the x interval is from -2 to 3, because of x=-2 and x=3
The upper line is y(u)=4x and the lower line is y(l)=x-5
So the area between the two lines is:
A=⌠y(u)-y(l) dx
A=⌠4x-x+5 dx
A=⌠3x+5 dx
A=[3x^2/2+5x]
A=[(3x^2+10x)/2], x=[-2,3]
A=(1/2)(27+30-(12-20))
A=(1/2)(57+8)
A=(1/2)(65)
A=32.5 u^2
15 & 16 & 17
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Answer: The graph is attached.
Step-by-step explanation:
1. Solve for y, as following:

2. The equation of the line in slope intercept form is:

Where m is the slope and b is the y-intercept.
3. In this case the equation of the line is:

then:

4. Find the x-intercept. Make y=0. Then:

5. Then, plot the line that passes through the points (0,7) and (4.9, 0).
6. The symbol of the inequality is < therefore, the line must be dashed and indicates that the region under the line must be shaded.
Then you obtain the graph attached.
4-3<9
5-3<9
6-3<9
and so on...