First, find the total area of pizza. The area of a rectangle is length times width.
Area = 21 x 36 = 756 sq. inches
Now, we must divide the total area with the largest square possible without any excess. So, we equate the area of the pizza to area of square:
A = s² = 756
s = 6 √21
Hence, the largest piece square possible has a side of 6 inches. Then, we divide the total area of the pizza by the area of each square piece to find the number of pieces;
756/6² = 21
Thus, there would be 21 pieces of 6-in square piece of pizza.
The answer is 24 root 3 or 41.56921938.
Answer:
lowest:8 more:16 32 64
Step-by-step explanation:
In the first octant, the given plane forms a triangle with vertices corresponding to the plane's intercepts along each axis.



Now that we know the vertices of the surface

, we can parameterize it by

where

and

. The surface element is

With respect to our parameterization, we have

, so the surface integral is
Answer:
not completely sure but I think its B